随笔- 361 文章- 7 评论- 26 阅读- 50万

先说最简单的，适合简单数据

一、使用controller as

<body ng-controller="ParentCtrl as parent">
    <input ng-model="parent.name" /> {{parent.name}}
    <div ng-controller="ChildCtrl as child">
      <input ng-model="child.name" /> {{child.name}} - {{parent.name}}
    </div>
</body>

这样parentCtrl中的数据也可以显示在嵌套在其中的childCtrl了

二、使用$rootScope 或 $parent

<body ng-controller="ParentCtrl">
    <input ng-model="name" /> {{name}}
    <div ng-controller="ChildCtrl">
        <input ng-model="name" /> {{name}} - {{$parent.name}}
    </div>
</body>

三、使用$broadcast，$emit和$on

从上往下—— $broadcast 把事件广播给所有子controller
从下往上—— $emit 将事件冒泡传递给父controller
$on —— angularjs的事件注册函数

<div ng-app="app" ng-controller="parentCtrl">
    <div ng-controller="childCtrl1">name :
        <input ng-model="name" type="text" ng-change="change(name);" />
    </div>
    <div ng-controller="childCtrl2">Ctr1 name:
        <input ng-model="ctrl1Name" />
    </div>
</div>

angular.module("app", []).controller("parentCtrl",function ($scope) {
    //注册Ctrl1NameChange事件
    $scope.$on("Ctrl1NameChange", function (event, msg) {
        console.log("parent", msg);
        $scope.$broadcast("Ctrl1NameChangeFromParent", msg);
    });
}).controller("childCtrl1", function ($scope) {
    $scope.change = function (name) {
        console.log("childCtrl1", name);
        //冒泡Ctrl1NameChange事件，将name传给父级controller
        $scope.$emit("Ctrl1NameChange", name);
    };
}).controller("childCtrl2", function ($scope) {
    //
    $scope.$on("Ctrl1NameChangeFromParent",function (event, msg) {
        console.log("childCtrl2", msg);
        $scope.ctrl1Name = msg;
    });
});

jsfiddle链接：http://jsfiddle.net/whitewolf/5JBA7/15/

参看：

http://www.cnblogs.com/whitewolf/archive/2013/04/16/3024843.html
http://stackoverflow.com/questions/21287794/angularjs-controller-as-syntax-clarification