UVa 400 - Unix ls

每行最多60个字符
在尽量少的行中将字符串按字典序向下输出

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>

using namespace std;

const int maxn = 100;

struct ceil{
    char s[maxn];
    int len;
};
struct ceil p[maxn+50], temp;

bool cmp( struct ceil x, struct ceil y )
{
    if( strcmp( x.s, y.s ) > 0 )    return x.s > y.s;
}

int main()
{
    int n, i, j;
    int line, row;
    while( ~scanf("%d",&n) ){
        int M = -1;
        for( i = 0; i < n; i++ ){
            scanf("%s",p[i].s);
            p[i].len = strlen(p[i].s);
            M = p[i].len > M ? p[i].len : M;
        }
        line = 0;
        int M2 = M + 2;
        while( M + M2 <= 60 ){
            line++;
            M += M2;
        }
        line++;
        row = n / line;
        if( row*line < n )
            row++;
        int last = row*line - n;
        sort(p,p+n,cmp);
        puts("------------------------------------------------------------");
        for( i = 0; i < row; i++ ){
            int num = 0;
            for( j = 0; j < line; j++ ){
                if( n == 0 )    break;
                if( last > 0 && i > row - last - 1 && j == line-1 )     continue;
                printf("%s",p[i+num*row].s);
                for(int k = 0; k < M2 - 2 - p[i+num*row].len; k++ )
                        printf(" ");
                if(j != line-1 && n != 1 ){
                    if( last > 0  ){
                        if( i > row - last - 1){
                            if(j != line-2 )
                                printf("  ");}
                        else    printf("  ");
                    }
                    else printf("  ");
                }

                num++;
                n--;
            }
            puts("");
        }

    }
    return 0;
}
posted @ 2018-01-22 17:50  JinxiSui  阅读(100)  评论(0编辑  收藏  举报