python 输入一行字符,分别统计出其中英文字母、空格、数字和其它字符的个数。

一、参考解法:

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s =input('请输入字符串:')
dic={'letter':0,'integer':0,'space':0,'other':0}
for i in s:
    if i >'a' and i<'z' or i>'A' and i<'Z' :
        dic['letter'] +=1
    elif i in '0123456789':
        dic['integer'] +=1
    elif i ==' ':
        dic['space'] +=1
    else:
        dic['other'] +=1
         
print('统计字符串:',s)
print(dic)
print('------------显示结果2---------------'
for i in dic:
    print('%s='%i,dic[i])
print('------------显示结果3---------------'
for key,value in dic.items():
    print('%s='%key,value)

 

二、参考解法:

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tmpStr = input('请输入字符串:')
alphaNum=0
numbers=0
spaceNum=0
otherNum=0
for i in tmpStr:
    if i.isalpha():
        alphaNum +=1
    elif i.isnumeric():
        numbers +=1
    elif i.isspace():
        spaceNum +=1
    else:
        otherNum +=1
print('字母=%d'%alphaNum)
print('数字=%d'%numbers)
print('空格=%d'%spaceNum)
print('其他=%d'%otherNum)

 

三、参考解法:

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InPut = input('请输入字符串:')
letters  = [ ]
spaces = [ ]
digits   = [ ]
others = [ ]
for i in iter(InPut):
    if i.isalpha():
        letters.append(i)
    elif i.isspace():
        spaces.append(i)
    elif i.isdigit():
        digits.append(i)
    else:
        others.append(i)
print('''
字母: {}, 个数: {}
空格: {}, 个数: {}
数字: {}, 个数: {}
其他: {}, 个数: {}'''\
.format(letters, len(letters), spaces, len(spaces), digits, len(digits),others, len(others)))

 

四、参考解法:

使用正则表达式 re.findall()

复制代码
import re
s = input('请输入一串字符:')
char=re.findall(r'[a-zA-Z]',s)#以列表类型返回全部能匹配的子串
num=re.findall(r'[0-9]',s)
blank=re.findall(r' ',s)
chi=re.findall(r'[\u4E00-\u9FFF]',s)#汉字的Unicode编码范围
other = len(s)-len(char)-len(num)-len(blank)-len(chi)
print('字母',len(char),'\n数字',len(num),'\n空格',len(blank),'\n中文',len(chi),'\n其他',other)
复制代码

 五、参考解法:

使用正则表达式 re.match()

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import re
def splitFunc( ):
    tmpStr = input('请输入字符串:')
    charNum = 0
    digNum = 0
    spaceNum = 0
    otherNum = 0
    for i in range(len(tmpStr)):
        if re.match('[a-zA-Z]',tmpStr[i]):
            charNum +=1
        elif re.match('\d',tmpStr[i]):
            digNum +=1
        elif re.match('\s',tmpStr[i]):
            spaceNum +=1
        else:
            otherNum +=1
    print('字符:',charNum)
    print('数字:',digNum)
    print('空格:',spaceNum)
    print('其他:',otherNum)
splitFunc()
posted @ 2019-07-08 14:02  顺义姆巴佩  阅读(5966)  评论(0编辑  收藏  举报