一个很简单的jquery+xml+ajax的无刷新树结构(无css,后台是c#)

 

代码
using System;using System.Collections.Generic;using System.Linq;using System.Web;using System.Web.UI;using System.Web.UI.WebControls;using System.Data.Linq;using System.Xml;using System.Xml.Linq;namespace WebApplication3{ public partial class WebForm1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { int id =Convert.ToInt32(Request["parentID"]); GetXML(id); } public IList<Product> GetList() { returnnew List<Product>() { new Product(){ Id=1, ParentId=0, HasChild=1, Name="aaaaa" }, new Product(){ Id=2, ParentId=1, HasChild=1, Name="bbbb1" }, new Product(){ Id=3, ParentId=2, HasChild=0, Name="ccccc2" }, new Product(){ Id=4, ParentId=2, HasChild=0, Name="ddddd3" }, new Product(){ Id=5, ParentId=1, HasChild=0, Name="eeeeee4" }, new Product(){ Id=6, ParentId=3, HasChild=0, Name="ffffff5" }, new Product(){ Id=7, ParentId=4, HasChild=0, Name="ggggggg6" }, new Product(){ Id=8, ParentId=7, HasChild=0, Name="hhhhhhh7" }, new Product(){ Id=9, ParentId=0, HasChild=0, Name="jjjjjjj8" }, new Product(){ Id=10,ParentId=0, HasChild=0, Name="yyyyyyyy9" } }; } /// <summary> /// 通过父节点读取子节点并且拼接成xml给前台 /// </summary> /// <param name="parentId"></param> public void GetXML(int parentId) { List<Product> list = GetList().Where(x => x.ParentId == parentId).ToList(); XElement xElement = new XElement("textTree"); foreach (Product p in list) { xElement.Add(new XElement("value", new XAttribute("id", p.Id),p.Name)); } xElement.Save("d:\\kissnana.xml"); XmlDocument xdocument = new XmlDocument(); xdocument.Load("d:\\kissnana.xml"); Response.ContentType = "text/xml"; xdocument.Save(Response.OutputStream); Response.End(); } } public class Product { public int Id{set;get;} public int ParentId{set;get;} public int HasChild{set;get;} public string Name{set;get;} }}

 

 

思路很简单,后台利用xml送往前台通过jquery 接收处理拼接ul,li

 

原理(利用<li>中嵌套<ul>的方式,局部读取一节点下的所有直属子节点,每次点击读取,读取过的话,

 

则进入GetDisplayOrNot()方法判断显示和隐藏节点)

 

 

 

html代码:

<body>
<form id="form1" runat="server">
<input type="button" value="text" onclick="LoadXml(0)"/>
<div id="root">
</div>
</form>
</body>

 

 

 

前台代码:

1 <script type="text/javascript">
2
3
4 var object1 =null;
5 function LoadXml(id) {
6 $.ajax({
7 type: "post",
8 url:"WebForm1.aspx?parentID="+id,
9 dataType:"xml",
10 success: createTree
11
12 });
13
14 }
15
16 // 思路是每个父节点产生一个ul孩子并且ajax读取该父亲的直接儿子,拼接树
17  function createTree(xml) {
18 var obj = object1 ==null? ("#root") : (object1);//判断是不是第一次加载,如果第一次加载则是最外的div的id,否则是父节点
19   $(obj).append("<UL class='ULfather' >");//添加ul对象
20  
21 $(xml).find("value").each(function() {//从xml里读出所有value节点信息,得到当前层次节点
22  //拼接<li>和<a>,属性通过xml中的value节点的属性id和节点文本进行拼接
23   $(obj).children(".ULfather").append("<li><a id="+ $(this).attr("id") +">"+ $(this).text() +"</a></li>");
24
25 var alink ="#"+ $(this).attr("id"); //得到当前超链接对象
26  
27 $(alink).bind("click", function() { //超连接绑定点击事件
28  
29 if ($(alink +"+ul").size() <=0) {//如果数据已经绑定则无需再次绑定,(如果超链接下个元素是ul的话,说明数据已经绑过)
30   object1 = $(alink).parent("li");
31 LoadXml($(this).attr("id"))
32 }
33 else {
34
35 GetDisplayOrNot($(alink));
36 }
37
38 });
39 });
40 }
41
42
43 //节点显示或影藏
44  function GetDisplayOrNot(obj) {
45 if ($(obj).parent("li").children("ul").is(":hidden")) {
46 $(obj).parent("li").children("ul").css("display", "block");
47 }
48 else {
49 $(obj).parent("li").children("ul").css("display", "none");
50 }
51 }
52
53
54
55
56  </script>

 

 

 

后台:

 

 

 

 

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.Linq;
using System.Xml;
using System.Xml.Linq;

namespace WebApplication3
{
    public partial class WebForm1 : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            int id =Convert.ToInt32(Request["parentID"]);
            GetXML(id);
        }

        public IList<Product> GetList() 
        {
            return new List<Product>()
           {
              new Product(){ Id=1, ParentId=0, HasChild=1, Name="aaaaa" },
              new Product(){ Id=2, ParentId=1, HasChild=1, Name="bbbb1" },
              new Product(){ Id=3, ParentId=2, HasChild=0, Name="ccccc2" },
              new Product(){ Id=4, ParentId=2, HasChild=0, Name="ddddd3" },
              new Product(){ Id=5, ParentId=1, HasChild=0, Name="eeeeee4" },
              new Product(){ Id=6, ParentId=3, HasChild=0, Name="ffffff5" },
              new Product(){ Id=7, ParentId=4, HasChild=0, Name="ggggggg6" },
              new Product(){ Id=8, ParentId=7, HasChild=0, Name="hhhhhhh7" },
              new Product(){ Id=9, ParentId=0, HasChild=0, Name="jjjjjjj8" },
              new Product(){ Id=10,ParentId=0, HasChild=0, Name="yyyyyyyy9" }
           };
        }


        /// <summary>
        /// 通过父节点读取子节点并且拼接成xml给前台
        /// </summary>
        /// <param name="parentId"></param>
        public void GetXML(int parentId) 
        {
            List<Product> list = GetList().Where(x => x.ParentId == parentId).ToList();
            
            XElement xElement = new XElement("textTree");
            foreach (Product p in list) 
            {
                xElement.Add(new XElement("value", new XAttribute("id", p.Id),p.Name));
            }
            xElement.Save("d:\\kissnana.xml");
            XmlDocument xdocument = new XmlDocument();
            xdocument.Load("d:\\kissnana.xml");
            Response.ContentType = "text/xml";
            xdocument.Save(Response.OutputStream);
            Response.End();
        }

    }

    public class Product
    {
       public int Id{set;get;}
       public int ParentId{set;get;}
       public int HasChild{set;get;}
       public string Name{set;get;}
    }
}

 

呵呵,一个很菜鸟的无刷新树,只是给大家一点点写树的思路,谢谢!
posted @ 2010-06-01 17:43  逆时针の风  阅读(1991)  评论(1编辑  收藏  举报