projectEuler pro6

Problem 6

Published on Friday, 14th December 2001, 06:00 pm; Solved by 196379

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

JAVA:

public class P006 {
public static void main(String[] args){
int sum1 = 0;
int sum2 = 0;
for(int i=1;i<=100;i++){
sum1+=i*i;
}
sum2 = 5050*5050;
System.out.print(sum2-sum1);
}
}