WebApi 内容协商 简单区分JSON 和 Xml

Accept:响应可接收的媒体类型,如"application/json"、"application/xml",或者自定义媒体类型,如"application/vnd.example+xml"。

 

当我们希望接收到的是JSON时

private void button2_Click(object sender, EventArgs e)
        {
            HttpWebRequest request=(HttpWebRequest) WebRequest.Create("http://localhost:20137/api/Demo?Name=张三&Gender=M&age=22");
            request.Method = "GET";
            request.Accept = "application/json"

            using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
            {


                using (StreamReader reader = new StreamReader(response.GetResponseStream()))
                {
                    string result = reader.ReadToEnd();
                    this.textBox1.Text = result;
                }
            }
        }
public IHttpActionResult Get([FromUri]Person person)
        {
            return Ok(person);
        }

返回  {"Name":"张三","Gender":"M","Age":22}

当我们希望返回的是XML时

private void button2_Click(object sender, EventArgs e)
        {
            HttpWebRequest request=(HttpWebRequest) WebRequest.Create("http://localhost:20137/api/Demo?Name=张三&Gender=M&age=22");
            request.Method = "GET";
            request.Accept = "application/xml";

            using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
            {


                using (StreamReader reader = new StreamReader(response.GetResponseStream()))
                {
                    string result = reader.ReadToEnd();
                    this.textBox1.Text = result;
                }

              
            }
        }
public IHttpActionResult Get([FromUri]Person person)
        {
            return Ok(person);
        }

返回

<Person xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/WebApi.Models">
<
Age>22</Age>
<
Gender>M</Gender>
<
Name>张三</Name>
</
Person>

 

  

  

 

posted @ 2021-11-09 06:38  zq爱生活爱代码  阅读(124)  评论(0编辑  收藏  举报