【动态树】[BZOJ2002] Bounce 弹飞绵羊
实际上就是动态树的模版加上一个维护每一条链的size这样就可以吧一次弹射看成一条路径,然后统计这个路径上的size实际上就是经过了多少个节点然后没什么了。。
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 200000;
int ch[MAXN+10][2], Fa[MAXN+10];
int que[MAXN+10], sz[MAXN+10];
bool rev[MAXN+10];
bool isroot(int u){return ch[Fa[u]][0] != u && ch[Fa[u]][1] != u;}
void Rotate(int u){
int x = Fa[u], y = Fa[x];
bool md = ch[x][1] == u;
Fa[u] = y;
if(!isroot(x)) ch[y][ch[y][1] == x] = u;
ch[x][md] = ch[u][!md]; Fa[ch[u][!md]] = x;
ch[u][!md] = x; Fa[x] = u;
sz[x] = sz[ch[x][0]] + sz[ch[x][1]] + 1;
}
void push_down(int u){
if(rev[u]){
rev[u] ^= 1; rev[ch[u][0]] ^= 1; rev[ch[u][1]] ^= 1;
swap(ch[u][0], ch[u][1]);
}
}
void Splay(int u){
int now = u;
que[0] = 1; que[1] = now;
while(!isroot(now)){
que[++que[0]] = Fa[now];
now = Fa[now];
}
for(;que[0];que[0]--) push_down(que[que[0]]);
while(!isroot(u)){
int x = Fa[u], y = Fa[x];
if(!isroot(x)){
if((ch[x][0] == u) ^ (ch[y][0] == x)) Rotate(u);
else Rotate(x);
}
Rotate(u);
}
sz[u] = sz[ch[u][0]] + sz[ch[u][1]] + 1;
}
void access(int u){
int up = 0;
while(u != 0){
Splay(u);
ch[u][1] = up;
up = u; u = Fa[u];
}
}
void root(int u){
access(u);
Splay(u);
rev[u] ^= 1;
}
void Link(int x, int y){
root(x);
Fa[x] = y;
Splay(x);
}
void Cut(int x, int y){
root(x);
access(y);
Splay(y);
ch[y][0] = Fa[x] = 0;
}
/*bool Query(int x, int y){
access(x); Splay(x);
int u = x;
while(ch[u][0]) u = ch[u][0];
access(y); Splay(y);
int u1 = y;
while(ch[u1][0]) u1 = ch[u1][0];
return u == u1;
}*/
int Jp[MAXN+10];
int main(){
int n, m, a, b;
scanf("%d", &n);
for(int i=1;i<=n;i++){
scanf("%d", &a);
Jp[i] = min(i+a, n+1);
Link(Jp[i], i);
}
int ord;
scanf("%d", &m);
for(int i=0;i<m;i++){
scanf("%d", &ord);
if(ord == 1){
scanf("%d", &a);
root(n+1);
access(a+1);
Splay(a+1);
printf("%d\n", sz[ch[a+1][0]]);
}
else{
scanf("%d %d", &a, &b);
Cut(a+1, Jp[a+1]);
Jp[a+1] = a + 1 + b;
if(a + b + 1 > n) Jp[a+1] = n+1;
Link(Jp[a+1], a+1);
}
}
return 0;
}