angularJS前台传list数组,后台springMVC接收数组

有时候需要在前台自定义对象,然后把对象封装在list中,在传送到后台,这样的思想也比较合理

1. 前台代码

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$scope.saveScore = function () {
    $scope.userScoreList = new Array();//自定义数组
    angular.forEach ($scope.records, function (record, index) {
         
        if (record.score != null) {
            $scope.userScoreModel = {'userAnswerId'null,'score'null};//自定义对象结构
            $scope.userScoreModel.userAnswerId = record.userAnswerId;//赋值
            $scope.userScoreModel.score = record.score;
             
            $scope.userScoreList.push($scope.userScoreModel);//把对象封装在集合中
            debugger;
        }
    });
     
    if ($scope.userScoreList != null && $scope.userScoreList.length > 0) {
        var fd = new FormData();// 使用angularJS的FormData封装要传送的数据
        var userScoreRecords = angular.toJson($scope.userScoreList);//把对象(集合)转换为json串
        fd.append('userScoreRecords', userScoreRecords);//参数放入formData中
        debugger;//使用 debugger模式查看传值情况
        $http.post('/reviewProcess/save', fd, { //使用post方法 传送formdata对象
            transformRequest: angular.identity, //使用angular传参认证
            headers: {
                'Content-Type': undefined //设置请求头
            }
        })
        .success(function (data){
            toastr.success("success");
        })
        .error(function (data) {
            toastr.success("failed");
        });
    }
};

  2. 后台接收

 

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@ResponseBody
  @RequestMapping(value = "/reviewProcess/save", method = RequestMethod.POST)
  public void saveUserScore (@RequestParam("userScoreRecords") String userScoreRecords) { //使用requestparam接收前台传送的json串
      System.out.println(userScoreRecords);
      ObjectMapper mapper = new ObjectMapper(); // 使用fastJson的ObjectMapper反序列化json串为对象
      UserScoreModel record = null;
      try {
          JSONArray jsonArray = new JSONArray (userScoreRecords); //在后台把json串转换为json数组
          for (int i =0; i < jsonArray.length(); i++) {
              record = mapper.readValue(jsonArray.getJSONObject(i).toString(), UserScoreModel.class); //获取json数组的json对象并且反序列化为对应的对象
              System.out.println(record); // 得到对象后后台即可操作
          }
      catch (Exception e) {
          logger.error(e.getMessage(), e);
      }
  }

  

posted @ 2017-05-08 14:30  jeremy1888  阅读(310)  评论(0编辑  收藏  举报