Java并发编程:CountDownLatch、CyclicBarrier和Semaphore

参考importnew

CountDownLatch用法

CountDownLatch类位于java.util.concurrent包下,利用它可以实现类似计数器的功能。比如有一个任务A,它要等待其他4个任务执行完毕之后才能执行,此时就可以利用CountDownLatch来实现这种功能了。

CountDownLatch类只提供了一个构造器:

 public CountDownLatch(int count) { }; //参数count为计数值 

然后下面这3个方法是CountDownLatch类中最重要的方法:

public void await() throws InterruptedException { };   //调用await()方法的线程会被挂起,它会等待直到count值为0才继续执行
public boolean await(long timeout, TimeUnit unit) throws InterruptedException { };  //和await()类似,只不过等待一定的时间后count值还没变为0的话就会继续执行
public void countDown() { };  //将count值减1

Demo:

 1 package com.zxd.concurrent.learning;
 2 
 3 import java.util.concurrent.CountDownLatch;
 4 
 5 /**
 6  * @Project ConcurrentLearning
 7  * @Package com.zxd.concurrent.learning
 8  * @Author:zouxiaodong
 9  * @Description:
10  * @Date:Created in 10:57 2018/3/21.
11  */
12 public class CountDownLatchTest {
13 
14     public static void main(String[] args) throws InterruptedException {
15         System.out.println("主线程"+Thread.currentThread().getName()+"正在执行.......");
16         CountDownLatch latch = new CountDownLatch(2);
17         ThreadTest test_1 = new ThreadTest(latch,3000);
18         ThreadTest test_2 = new ThreadTest(latch,5000);
19         test_1.start();
20         test_2.start();
21         System.out.println("等待2个子线程执行完毕........");
22         latch.await();
23         System.out.println("2个子线程已经执行完毕..................");
24         System.out.println("继续执行主线程..................");
25         System.out.println("主线程其他逻辑执行..................");
26     }
27 }
28 
29 class ThreadTest extends Thread{
30     private CountDownLatch countDownLatch = null;
31     private long sleep = 0L;
32 
33     public ThreadTest(CountDownLatch countDownLatch,long sleep) {
34         this.countDownLatch = countDownLatch;
35         this.sleep = sleep;
36     }
37 
38     @Override
39     public void run() {
40         try {
41             System.out.println("子线程"+Thread.currentThread().getName()+"正在执行.......");
42             Thread.sleep(sleep);
43             System.out.println("子线程"+Thread.currentThread().getName()+"执行完毕.......");
44             System.out.println("--------------countDownLatch.getCount()前="+countDownLatch.getCount());
45             countDownLatch.countDown();
46             System.out.println("--------------countDownLatch.getCount()后="+countDownLatch.getCount());
47         } catch (InterruptedException e) {
48             e.printStackTrace();
49         }
50     }
51 }
CountDownLatch

运行结果:


 

CyclicBarrier用法

字面意思回环栅栏,通过它可以实现让一组线程等待至某个状态之后再全部同时执行。叫做回环是因为当所有等待线程都被释放以后,CyclicBarrier可以被重用。我们暂且把这个状态就叫做barrier,当调用await()方法之后,线程就处于barrier了。

CyclicBarrier类位于java.util.concurrent包下,CyclicBarrier提供2个构造器:

public CyclicBarrier(int parties, Runnable barrierAction) {
}
 
public CyclicBarrier(int parties) {
}

参数parties指让多少个线程或者任务等待至barrier状态;参数barrierAction为当这些线程都达到barrier状态时会执行的内容。

然后CyclicBarrier中最重要的方法就是await方法,它有2个重载版本:

//用来挂起当前线程,直至所有线程都到达barrier状态再同时执行后续任务
public int await() throws InterruptedException, BrokenBarrierException {  

};

//让这些线程等待至一定的时间,如果还有线程没有到达barrier状态就直接让到达barrier的线程执行后续任务
public int await(long timeout, TimeUnit unit)throws InterruptedException,BrokenBarrierException,TimeoutException { 

};

Demo:

package com.zxd.concurrent.learning;

import java.util.concurrent.CyclicBarrier;

/**
 * @Project ConcurrentLearning
 * @Package com.zxd.concurrent.learning
 * @Author:zouxiaodong
 * @Description:
 * @Date:Created in 17:41 2018/3/21.
 */
public class CyclicBarrierTest {

    public static void main(String[] args) throws InterruptedException {
        int i = 4;
//        CyclicBarrier cyclicBarrier = new CyclicBarrier(i);
        CyclicBarrier cyclicBarrier = new CyclicBarrier(i, new Runnable() {
            @Override
            public void run() {
                System.out.println("当前线程号为:"+Thread.currentThread().getName()+",所有线程已到达barrier.................");
            }
        });

        for(int m=0;m<i;m++){
            new Writer(cyclicBarrier).start();
        }

        Thread.sleep(10000);

        System.out.println("CyclicBarrier重用....................");

        for(int m=0;m<i;m++){
            new Writer(cyclicBarrier).start();
        }

    }
    static class Writer extends Thread{
        private CyclicBarrier cyclicBarrier;

        public Writer(CyclicBarrier cyclicBarrier){
            this.cyclicBarrier = cyclicBarrier;
        }

        @Override
        public void run(){
            try {
                System.out.println("子线程"+Thread.currentThread().getName()+"正在执行写入.......");
                Thread.sleep(2000);
                System.out.println("子线程"+Thread.currentThread().getName()+"写入完成.......");
                cyclicBarrier.await();
            } catch (Exception e) {
                e.printStackTrace();
            }
            System.out.println("所有线程写入完成,继续处理线程"+Thread.currentThread().getName()+"其他任务..............");
        }
    }
}
CyclicBarrier

运行结果:


 

Semaphore用法

Semaphore翻译成字面意思为信号量Semaphore可以控同时访问的线程个数,通过 acquire() 获取一个许可,如果没有就等待,而 release() 释放一个许可。

Semaphore类位于java.util.concurrent包下,它提供了2个构造器:

public Semaphore(int permits) {          //参数permits表示许可数目,即同时可以允许多少线程进行访问
    sync = new NonfairSync(permits);
}
public Semaphore(int permits, boolean fair) {    //这个多了一个参数fair表示是否是公平的,即等待时间越久的越先获取许可
    sync = (fair)? new FairSync(permits) : new NonfairSync(permits);
}

下面说一下Semaphore类中比较重要的几个方法,首先是acquire()release()方法:

public void acquire() throws InterruptedException {  }     //获取一个许可
public void acquire(int permits) throws InterruptedException { }    //获取permits个许可
public void release() { }          //释放一个许可
public void release(int permits) { }    //释放permits个许可

acquire()用来获取一个许可,若无许可能够获得,则会一直等待,直到获得许可。

release()用来释放许可。注意,在释放许可之前,必须先获获得许可。

这4个方法都会被阻塞,如果想立即得到执行结果,可以使用下面几个方法:

public boolean tryAcquire() { };    //尝试获取一个许可,若获取成功,则立即返回true,若获取失败,则立即返回false
public boolean tryAcquire(long timeout, TimeUnit unit) throws InterruptedException { };  //尝试获取一个许可,若在指定的时间内获取成功,则立即返回true,否则则立即返回false
public boolean tryAcquire(int permits) { }; //尝试获取permits个许可,若获取成功,则立即返回true,若获取失败,则立即返回false
public boolean tryAcquire(int permits, long timeout, TimeUnit unit) throws InterruptedException { }; //尝试获取permits个许可,若在指定的时间内获取成功,则立即返回true,否则则立即返回false

可以通过availablePermits()方法得到可用的许可数目.
Demo:

package com.zxd.concurrent.learning;

import java.util.concurrent.Semaphore;

/**
 * @Project ConcurrentLearning
 * @Package com.zxd.concurrent.learning
 * @Author:zouxiaodong
 * @Description:
 * @Date:Created in 18:13 2018/3/21.
 */
public class SemaphoreTest {

    public static void main(String[] args){
        int person = 8;
        Semaphore semaphore = new Semaphore(5);
        for(int i = 0;i < person;i++){
            new Thread(new Person(person,semaphore)).start();
        }
    }
    static class Person implements Runnable{
        private int num;
        private Semaphore semaphore;

        public Person(int num, Semaphore semaphore) {
            this.num = num;
            this.semaphore = semaphore;
        }

        @Override
        public void run() {
            try {
                System.out.println("1.线程:"+Thread.currentThread().getName()+"准备获取许可,可用semaphore数:"+semaphore.availablePermits());
                semaphore.acquire();
                System.out.println("2.线程:"+Thread.currentThread().getName()+"占用一个许可,可用semaphore数:"+semaphore.availablePermits());
                Thread.sleep(2000);
                semaphore.release();
                System.out.println("3.线程:"+Thread.currentThread().getName()+"释放一个许可,可用semaphore数:"+semaphore.availablePermits());
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

        }
    }
}
Semaphore

运行结果:

posted @ 2019-06-26 16:09  CoderZZZ  阅读(248)  评论(0编辑  收藏  举报