摘要: 1 def remove_odd_elements(mylist:list): 2 return [element for element in mylist if(element//2*2==element)] 3 4 # a=[12,15,3,10] 5 # print(remove_odd_e 阅读全文
posted @ 2021-03-15 18:05 墨鳌 阅读(65) 评论(0) 推荐(0) 编辑