PAT (Advanced Level) Practice 1155 Heap Paths (30分) （递归+数组建树，递归+vector输出，make_heap判断）
1.题目
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1<N≤1,000), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all.
Sample Input 1:
8
98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap
Sample Input 2:
8
8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap
Sample Input 3:
8
10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap2.题目分析
1.建树
开始思路跑偏了，一直想着数据结构题库里那个层序遍历输出的题，忘了数据结构老师说过：
完全二叉树按照数组存放的时候，2*i是左子树，2*i+1是右子树 （失败……）
2.输出
用vector记录之前的数据，观察发现是遍历（后序遍历）到叶子节点的时候就输出一次，输出后将最后一个删除，再接着遍历
3.判断
分别使用make_heap建立大根堆、小根堆，以此判断就行
3.代码
#include<iostream>
#include<algorithm>
#include<functional>
#include<vector>
#include<cstdio>
using namespace std;
int list[1001];
typedef struct node * tree;
struct node
{
int data;
tree left;
tree right;
};
tree creat(tree origin,int list[],int i,int n)
{
if (i > n)return NULL;
if(!origin)
origin = (tree)malloc(sizeof(struct node));
origin->left = origin->right = NULL;
origin->data = list[i];
origin->left = creat(origin->left, list, 2 * i,n);
origin->right = creat(origin->right, list, 2 * i+1, n);
return origin;
}
void output(tree origin, vector<int>out)
{
if (!origin)return;
if (origin->left==NULL&&origin->right==NULL)
{
out.push_back(origin->data);
int size = out.size();
for (int i = 0; i < size; i++)
printf("%d%s", out[i], i == size - 1 ? "" : " ");
printf("\n");
out.pop_back();
return;
}
out.push_back(origin->data);
output(origin->right, out);
output(origin->left, out);
}
int main()
{
int n,count=1;
cin >> n;
tree origin = (tree)malloc(sizeof(struct node));
origin->left = origin->right = NULL;
for (int i = 1; i <=n; i++)
cin >> list[i];
origin = creat(origin, list, 1, n);
vector<int>out;
output(origin, out);
vector<int>com;
for (int i = 1; i <=n; i++)
com.push_back(list[i]);
bool big = true;
make_heap(com.begin(), com.end(), less<int>());
for (int i = 1; i <= n; i++)
{
if (list[i] != com[i - 1]) { big = false; break; }
}
if (!big)
{
make_heap(com.begin(), com.end(), greater<int>());
for (int i = 1; i <= n; i++)
{
if (list[i] != com[i - 1]) { printf("Not Heap\n"); return 0; }
}
printf("Min Heap\n");
}
else
printf("Max Heap\n");
}