力扣92.反转链表Ⅱ

 

将自己的思路记录一下

题目:【https://leetcode.cn/problems/reverse-linked-list-ii/description/?envType=study-plan-v2&envId=top-interview-150

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 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     struct ListNode *next;
 6  * };
 7  */
 8 struct ListNode* reverseBetween(struct ListNode* head, int left, int right) {
 9     if (left >= right)
10         return head;
11     struct ListNode* prev = NULL;
12     struct ListNode* curr = head;
13     struct ListNode* next = NULL;
14 
15     for (int i = 1; i < left; ++i) {
16         prev = curr;
17         curr = curr->next;
18     }
19     struct ListNode* start = curr;
20 
21     for (int i = 0; i <= right - left; ++i) {
22         next = curr->next;
23         curr->next = prev;
24         prev = curr;
25         curr = next;
26     }
27 
28     if (start->next) start->next->next = prev;
29     start->next = curr;
30     return left <= 1 ? prev : head;
31 }
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posted @   J&YANG  阅读(3)  评论(0编辑  收藏  举报
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