C 阿宁的大背包【2023牛客寒假算法基础集训营6】

C 阿宁的大背包

原题链接

代码

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#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<vector>
#include<queue>
using namespace std;

#define X first
#define Y second

typedef pair<int,int> pii;
typedef long long LL;
const char nl = '\n';
const int N = 1e3+10;
const int M = 1e6+10;
const int mod = 1e9+7;
int n;
LL a[N],b[N];
LL ans;

void solve(){
	cin >> n;
    int nt = n;
    if(n % 2 == 0){
        int i = n / 2,j = n / 2 + 1;
        while(n){
            if(n % 2){
                a[i] = n;
                i --;
            }
            else{
                a[j] = n;
                j ++;
            }
            n --;
        }
    }
    else{
        a[n / 2 + 1] = n;
        n -= 1;
        int i = n / 2,j = n / 2 + 2;
        while(n){
            if(n % 2){
                a[i] = n;
                i --;
            }
            else{
                a[j] = n;
                j ++;
            }
            n --;
        }
    }
    for(int i = 1; i <= nt; i ++ )b[i] = a[i];
    for(int i = 1; i < nt; i ++ ){
        for(int j = 1; j <= nt - i; j ++ ){
            a[j] = (a[j] + a[j + 1])%mod;
        }
    }
    cout << a[1] << nl;
	for(int i = 1; i <= nt; i ++ )cout << b[i] << " ";

}

int main(){
	ios::sync_with_stdio(false);
	cin.tie(0),cout.tie(0);

	solve();
}

构造(简化写法)

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    int p1=0,p2=n+1;
    for(int i=1;i<=n;i++){
        if(i&1)a[++p1]=i;	//奇数
        else a[--p2]=i;
    }