HDU 1002 A + B Problem II

题目链接：HDU 1002 A + B Problem II

题目大意：
计算\(A+B\)。

题解：
高精度模板题，注意对数组的初始化。

#include <iostream>
#include <string>
#include <cstring>
using namespace std;

struct BigNum {
	int num[1010], len;
} a, b, c;

void add(BigNum &a, BigNum &b, BigNum &c) {
	c.len = max(a.len, b.len);
	for (int i = 0; i < c.len; ++i) {
		c.num[i] = a.num[i] + b.num[i];
	}
	for (int i = 0; i < c.len; ++i) {
		if (c.num[i] > 9) {
			c.num[i + 1]++;
			c.num[i] -= 10;
		}
	}
	if (c.num[c.len])    c.len++;
}

void print(BigNum x) {
	for (int i = x.len - 1; i >= 0; --i) {
		cout << x.num[i];
	}
}

int main() {
	int T;
	cin >> T;
	for (int p = 1; p <= T; ++p) {
		string str;
		memset(a.num, 0, sizeof(a.num));
		memset(b.num, 0, sizeof(b.num));
		memset(c.num, 0, sizeof(c.num));
		cin >> str;
		int t = str.length();
		a.len = t;
		for (int i = 0; i < t; ++i) {
			a.num[i] = str[t - i - 1] - '0';
		}
		cin >> str;
		t = str.length();
		b.len = t;
		for (int i = 0; i < t; ++i) {
			b.num[i] = str[t - i - 1] - '0';
		}
		add(a, b, c);
		cout << "Case " << p << ":" << endl;
		print(a);
		cout << " + ";
		print(b);
		cout << " = ";
		print(c);
		if (p == T)		cout << endl;
		else			cout << endl << endl;
	}
	return 0;
}