组装数据--相同的clusterID合并在一起 左边是a接口 右边是B接口如 [{a接口},{b接口}]

组装成这种 

var BJData = [

[{"city": "无锡市","clusterID": 1, "y": 31.809979797058332}, { "city": "苏州市", "clusterID":1, "x": 120.7485913653},],

[{name:'北京'}, {name:'天津'}],

[{name:'北京'}, {name:'河南',type:"mt"}],

[{name:'北京'}, {name:'甘肃',type:"mt"}]

];

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data: {              centerdata:[                {"city": "无锡市","clusterID": 1,"y": 31.809979797058332},                {"city": "廊坊市","clusterID": 2,"y": 39.215436433250005},                {"city": "金华市","clusterID": 3,"y": 29.190387826775}               ],                 sizhoudata:[               { "city": "苏州市", "clusterID": 1, "x": 120.7485913653, },               {"city": "重庆市","clusterID": 2,"x": 120.5818049003},               {"city": "广汉市","clusterID": 3,"x": 140.5818049003}],            },

　　

　　用了两个for循环，会循环3*3=9次

?

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created() {              var newarr=[];              for(let i in this.centerdata ){                for(let j in this.sizhoudata){                   if(this.centerdata[i].clusterID==this.sizhoudata[j].clusterID){                      let arr=[this.centerdata[i],this.sizhoudata[j]]                      newarr.push(arr);                   }                }              }              console.log(newarr)            },