Python代码 | 井字棋

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import random   checkerboard = [     [0, 0, 0],     [0, 0, 0],     [0, 0, 0] ] i = 0 print(f"欢迎来玩井子棋，请在轮到你落子时输入你要下的位置，第x行，第y列，用逗号隔开，例如：1,2")     def print_board():     for row in checkerboard:         for col in row:             if col == 0:                 print("| ", end="")             if col == 1:                 print("|○", end="")             if col == -1:                 print("|×", end="")         print("|")     print()     def is_over():     for row in checkerboard:         if sum(row) == 3:             print("你赢了")             return True         if sum(row) == -3:             print("你输了")             return True       for y in range(3):         if checkerboard[0][y] + checkerboard[1][y] + checkerboard[2][y] == 3:             print("你赢了")             return True         if checkerboard[0][y] + checkerboard[1][y] + checkerboard[2][y] == -3:             print("你输了")             return True       if checkerboard[0][0] + checkerboard[1][1] + checkerboard[2][2] == 3:         print("你赢了")         return True     if checkerboard[0][0] + checkerboard[1][1] + checkerboard[2][2] == -3:         print("你输了")         return True     if checkerboard[0][2] + checkerboard[1][1] + checkerboard[2][0] == 3:         print("你赢了")         return True     if checkerboard[0][2] + checkerboard[1][1] + checkerboard[2][0] == -3:         print("你输了")         return True     if i == 9:         print("平局")         return True     # 电脑为后手，故胜利第一，防守第二，进攻第三 def computer_turn():     # 胜利     for x in range(3):         if sum(checkerboard[x]) == -2:             for y in range(3):                 if checkerboard[x][y] == 0:                     checkerboard[x][y] = -1                     return 0     for y in range(3):         if checkerboard[0][y] + checkerboard[1][y] + checkerboard[2][y] == -2:             for x in range(3):                 if checkerboard[x][y] == 0:                     checkerboard[x][y] = -1                     return 0     if checkerboard[0][0] + checkerboard[1][1] + checkerboard[2][2] == -2:         for j in range(3):             if checkerboard[j][j] == 0:                 checkerboard[j][j] = -1                 return 0     if checkerboard[0][2] + checkerboard[1][1] + checkerboard[2][0] == -2:         for j in range(3):             if checkerboard[j][2 - j] == 0:                 checkerboard[j][2 - j] = -1                 return 0       # 防守     for x in range(3):         if sum(checkerboard[x]) == 2:             for y in range(3):                 if checkerboard[x][y] == 0:                     checkerboard[x][y] = -1                     return 0     for y in range(3):         if checkerboard[0][y] + checkerboard[1][y] + checkerboard[2][y] == 2:             for x in range(3):                 if checkerboard[x][y] == 0:                     checkerboard[x][y] = -1                     return 0     if checkerboard[0][0] + checkerboard[1][1] + checkerboard[2][2] == 2:         for j in range(3):             if checkerboard[j][j] == 0:                 checkerboard[j][j] = -1                 return 0     if checkerboard[0][2] + checkerboard[1][1] + checkerboard[2][0] == 2:         for j in range(3):             if checkerboard[j][2 - j] == 0:                 checkerboard[j][2 - j] = -1                 return 0       # 进攻的写法比较随机，是卖给玩家唯一的破绽     vacancies = []     for x in range(3):         for y in range(3):             if checkerboard[x][y] == 0:                 vacancies.append((x, y))     x, y = vacancies[random.randint(0, len(vacancies) - 1)]     checkerboard[x][y] = -1     print_board() while True:     while True:         x, y = map(int, input(f"轮到你落子了，选择你要下的位置：").split(","))         if x > 3 or y > 3:             print("超出棋盘范围，请重新输入")             continue         if checkerboard[x - 1][y - 1] != 0:             print("该位置已有棋子，请重新输入")             continue         break     checkerboard[x - 1][y - 1] = 1     i += 1     print("")     print(f"第{i}子：")     print_board()     if is_over():         break       computer_turn()     i += 1     print("")     print(f"第{i}子：")     print_board()     if is_over():         break