2023-05-04-Binomial-Sum

\[[x^k]F(g(x)) = [x^k]\sum_{i = 0}^{k} [x^i]F(x)g^i(x) \]

posted @ 2023-07-05 11:57  Iridescent41  阅读(5)  评论(1)  编辑  收藏  举报