js金额转化大写

function intToChinese(money) {
    //汉字的数字
    var cnNums = new Array('零', '壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖');
    //基本单位
    var cnIntRadice = new Array('', '拾', '佰', '仟');
    //对应整数部分扩展单位
    var cnIntUnits = new Array('', '万', '亿', '兆');
    //对应小数部分单位
    var cnDecUnits = new Array('角', '分', '毫', '厘');
    //整数金额时后面跟的字符
    var cnInteger = '整';
    //整型完以后的单位
    var cnIntLast = '元';
    //最大处理的数字
    var maxNum = 999999999999999.9999;
    //金额整数部分
    var integerNum;
    //金额小数部分
    var decimalNum;
    //输出的中文金额字符串
    var chineseStr = '';
    //分离金额后用的数组，预定义
    var parts;
    if (money === '') { //不能用==
        return '';
    }
    money = parseFloat(money);
    if (money >= maxNum) {
        //超出最大处理数字
        return '';
    }
    if (money == 0) {
        chineseStr = cnNums[0] + cnIntLast + cnInteger;
        return chineseStr;
    }
    //转换为字符串
    money = money.toString();
    if (money.indexOf('.') == -1) {
        integerNum = money;
        decimalNum = '';
    } else {
        parts = money.split('.');
        integerNum = parts[0];
        decimalNum = parts[1].substr(0, 4);
    }
    //获取整型部分转换
    if (parseInt(integerNum, 10) > 0) {
        var zeroCount = 0;
        var IntLen = integerNum.length;
        for (var i = 0; i < IntLen; i++) {
            var n = integerNum.substr(i, 1);
            var p = IntLen - i - 1;
            var q = p / 4;
            var m = p % 4;
            if (n == '0') {
                zeroCount++;
            } else {
                if (zeroCount > 0) {
                    chineseStr += cnNums[0];
                }
                //归零
                zeroCount = 0;
                chineseStr += cnNums[parseInt(n)] + cnIntRadice[m];
            }
            if (m == 0 && zeroCount < 4) {
                chineseStr += cnIntUnits[q];
            }
        }
        chineseStr += cnIntLast;
    }
    //小数部分
    if (decimalNum != '') {
        var decLen = decimalNum.length;
        for (var i = 0; i < decLen; i++) {
            var n = decimalNum.substr(i, 1);
            if (n != '0') {
                chineseStr += cnNums[Number(n)] + cnDecUnits[i];
            }
        }
    }
    if (chineseStr == '') {
        chineseStr += cnNums[0] + cnIntLast + cnInteger;
    } else if (decimalNum == '') {
        chineseStr += cnInteger;
    }
    return chineseStr;
}