HDU 2896
AC自动机应用,隔了两三天再写稍显生疏,还是需要练习提高熟练度。
自动机状态数其实是个不太好估量的数字,本题查看discuss才发现,内存会被卡
#include <iostream>
#include <algorithm>
#include <queue>
#include <string>
#include <vector>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <string>
#include <stack>
#include <map>
#include <set>
#include <deque>
using namespace std;
const int maxc= 101;
const int maxs= 58030;
const int maxv= 205;
const int maxw= 10005;
const int maxn= 500;
struct Trie
{
int root, L;
int next[maxs][maxc], end[maxs], fail[maxs];
void Init()
{
L= 0;
root= NewNode();
}
int NewNode()
{
for (int i= 0; i< maxc; ++i){
next[L][i]= -1;
}
end[L++]= 0;
return L-1;
}
void Insert(char *s, int id)
{
int lth= strlen(s), now= root;
for (int i= 0; i< lth; ++i){
int idx= s[i]-' ';
if (-1== next[now][idx]){
next[now][idx]= NewNode();
}
now= next[now][idx];
}
end[now]= id;
}
void Build()
{
queue<int> Q;
fail[root]= root;
for (int i= 0; i< maxc; ++i){
if (-1== next[root][i]){
next[root][i]= root;
}
else{
fail[next[root][i]]= root;
Q.push(next[root][i]);
}
}
while (!Q.empty()){
int now= Q.front();
Q.pop();
for (int i= 0; i< maxc; ++i){
if (-1== next[now][i]){
next[now][i]= next[fail[now]][i];
}
else{
fail[next[now][i]]= next[fail[now]][i];
Q.push(next[now][i]);
}
}
}
}
int Query(char *s, int diag[])
{
int tot= 0, lth= strlen(s);
int now= root;
for (int i= 0; i< lth; ++i){
int idx= s[i]-' ';
now= next[now][idx];
int tmp= now;
while (root!= tmp){
if (end[tmp]){
int flag= 1;
for (int i= 0; i< tot; ++i){
if (diag[i]== end[tmp]){
flag= 0;
break;
}
}
if (flag){
diag[tot++]= end[tmp];
if (tot>= 3){
goto RET;
}
}
}
tmp= fail[tmp];
}
}
RET: sort(diag, diag+tot);
return tot;
}
}ac;
char virus[maxv], web[maxw];
int diag[4];
int main(int argc, char const *argv[])
{
int n, m;
scanf("%d", &n);
ac.Init();
for (int i= 1; i<= n; ++i){
scanf(" %s", virus);
ac.Insert(virus, i);
}
ac.Build();
scanf("%d", &m);
int cnt= 0;
for (int i= 1; i<= m; ++i){
scanf(" %s", web);
int tot= ac.Query(web, diag);
if (tot> 0){
++cnt;
printf("web %d:", i);
for (int j= 0; j< tot; ++j){
printf(" %d", diag[j]);
}
putchar('\n');
}
}
printf("total: %d\n", cnt);
return 0;
}