Java里数值类型转换

import static java.lang.System.out;

public class testOnNumber {
    public static void main(String[] args){
        //int转换成short，把低位截断给short
        int i = 0xa0001231;
        out.println(Integer.toBinaryString(i));
        out.println(i);
        short s = (short) i;
        out.println(s);

        //mask的效果差不多是把short转成unsigned，估计是因为s2 & mask的结果是int，而符号位为0
        out.println();
        short s2 = (short) 0x9004;
        int mask = 0xffff;
        out.println(Integer.toBinaryString(s2));
        out.println(Short.toUnsignedInt(s2));
        out.println(s2 & mask);
        out.println(s2);

        //可以据此推断出Java里数据存为二进制的方式是big-Endian?
        out.println();
        int i2 = 0x732132ab;
        out.println(Integer.toBinaryString(i2));
        short s3 = (short) i2;
        short s4 = (short) (i2 >> 16);
        out.println(Integer.toBinaryString(s3));
        out.println(Integer.toBinaryString(s4));
    }
}

输出结果：

10100000000000000001001000110001
-1610608079
4657

11111111111111111001000000000100
36868
36868
-28668

1110011001000010011001010101011
11001010101011
111001100100001