过滤莫文件夹下所有文件和子文件夹中的文件,并把路径打印出-----面对过程的编程

import os
def init(func):
    def wrapper(*args,**kwargs):
        res = func(*args,**kwargs)
        next(res)
        return res
    return wrapper

@init
def search(target):
    '找到文件的绝对路径'
   
while True:
        dir_name = yield
       
g = os.walk(dir_name)
        for i in g:
            for j in i[-1]:
                if len(j.split('.'))==1:
                     file_path = '%s\\%s'%(i[0],j)
                     #print(file_path)
                    
target.send(file_path)

@init
def opener(target):
    '打开文件,获取文件句柄'
   
while True:
        file_path = yield
        with
open(file_path,encoding='utf-8') as f:
            target.send((file_path,f))

@init
def cat(target):
    '读取文件内容'
   
while True:
        file_path,f=yield
        for
line in f:
            target.send((file_path,line))
           
@init
def grep(pattern,target):
    '过滤一行内容中有无Python'
   
while True:
        file_path,line = yield
        if
pattern in line:
            target.send(file_path)
           
@init
def unrepeat(target):
    '去重相同的文件路径'
   
file_path_l =''
   
while True:
        file_path =yield
        if
file_path !=  file_path_l:
            target.send(file_path)
            file_path_l=file_path

@init
def printer():
    '打印文件路径'
   
while True:
        file_path = yield
       
print(file_path)

g = search(opener(cat(grep('error',unrepeat(printer())))))
g.send('d:\\Program Files(x86)\\py_fallstack_s4')
posted @ 2017-04-12 17:29  study_python  阅读(608)  评论(0编辑  收藏  举报