FrogJmp 

 1         /// <summary>
 2         /// Solution
 3         /// 100/100
 4         /// </summary>
 5         /// <param name="X"></param>
 6         /// <param name="Y"></param>
 7         /// <param name="D"></param>
 8         /// <returns></returns>
 9         public static int solution(int X, int Y, int D)
10         {
11             int distance = Y - X;
12             int result = distance / D;
13             if (distance % D == 0)
14             {
15                 return result;
16             }
17             else
18             {
19                 return result + 1;
20             }
21         }

 

posted @ 2015-07-23 23:41  叫我霍啊啊啊  阅读(134)  评论(0)  编辑  收藏  举报