摘要: 小结论 数学相关: \(\displaystyle\sum_{k=1}^n \frac{1}{k} = \ln n\) \(C_n^m = C^{m-1}_{n-1} +C^m_{n-1}\) \(C^m_n = \frac{n}{m} * C^{m-1}_{n-1}\) \(C^0_n + C^1 阅读全文
posted @ 2019-11-12 18:38 Hs-black 阅读(146) 评论(0) 推荐(0) 编辑