摘要: 其他相关 # print(len(range(100))) # l = [1, 2, 3, 4, 5] # l_obj = l.__iter__() # l_obj = iter(l) # print(l_obj) # print(l_obj.__next__()) # print(next(l_o 阅读全文
posted @ 2018-05-17 19:20 HoneyCY 阅读(235) 评论(0) 推荐(0) 编辑