二级python对字频统计


问题(1):

txt=open("命运.txt","r").read()
for ch in",。?:":
    txt=txt.replace(ch,"")
d = {}
for ch in txt:
    d[ch]=d.get(ch,0)+1
ls=list(d.items())
ls.sort(key=lambda x:x[1],reverse=True)
a,b=ls[0]
print("{}:{}".format(a,b))

问题(2):

txt=open("命运.txt","r").read()
for ch in '\n':
    txt=txt.replace(ch,"")
d = {}
for ch in txt:
    d[ch]=d.get(ch,0)+1
ls = list(d.items())
ls.sort(key=lambda x:x[1], reverse=True) # 此行可以按照词频由高到低排序
for i in range(10):
    print(str(ls[i])[2],end="")

问题(3):

txt=open("命运.txt","r").read()
for ch in ' \n':
    txt=txt.replace(ch,"")
d = {}
for ch in txt:
    d[ch]=d.get(ch,0)+1
ls = list(d.items())
ls.sort(key=lambda x:x[1], reverse=True) # 此行可以按照词频由高到低排序
string=""
for i in range(len(ls)):
    s=str(ls[i]).strip("()")
    string=string+s[1]+':'+s[5:]+','
f=open("命运-频次排序.txt","w")
f.write(string)
f.close()
posted @ 2021-09-18 20:54  py佐料  阅读(116)  评论(0编辑  收藏  举报