把连续日期组织起来的算法

  一个日期数组,其中可能有连续的日期,要格式化成特定形式的字符串,例如:2010-8-1,2010-8-3,2010-8-4,2010-8-5,2010-8-10格式化成字符串“8.1;8.3-8.5;8.10”,可以用如下的算法:

  

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private string GetFormatDateString()
{
    List<DateTime> timeList = new List<DateTime>
    {
        new DateTime(2010,8,1),
        new DateTime(2010,8,3),
        new DateTime(2010,8,4),
        new DateTime(2010,8,5),
        new DateTime(2010,8,6),
        new DateTime(2010,8,7),
        new DateTime(2010,8,9),
        new DateTime(2010,8,11),
        new DateTime(2010,8,12)
    };
    string arr = "";
    int lastIndex = -1;
    for (int j = 0; j < timeList.Count; j++)
    {
        if (j > lastIndex)
        {
            int i = 1;
            while (timeList.Contains(timeList[j].AddDays(i)))
            {
                i++;
            }
            if (i == 1)
            {
                arr += timeList[j].Month + "." + timeList[j].Day + ";";
                lastIndex = j;
            }
            else
            {
                arr += timeList[j].Month + "." + timeList[j].Day + "-" + timeList[j + i - 1].Month + "." + timeList[j + i - 1].Day + ";";
                lastIndex = j + i - 1;
            }
        }
    }
    arr = arr.TrimEnd(';');
    return arr;
}
posted @   Qubook  阅读(370)  评论(0编辑  收藏  举报
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