获取HTML源代码 

  1. import requests
def getHTMLText(url):
    try:
	headers = {"User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.87 Safari/537.36"}
        r = requests.get(url,headers = headers)		
        r.encoding = r.apparent_encoding
        return r.text
    except:
    	print("URL错误：",url)

    　　

posted @ 2018-03-30 14:34  Haley_haley  阅读(174)  评论(0)  编辑  收藏  举报