STM32 高级定时TIM 死区时间计算--C语言实现
#include <stdio.h> #include <math.h> #include <stdlib.h> #include <string.h> int DTG[8]={0,0,0,0,0,0,0,0}; ///是十进制转二进制 int dectobin(int n) { int sum = 0; int y, x = 1; // y表示余数,x为叠加的系数 while (n != 0) { y = n % 2; sum += x * y; x *= 10; n /= 2; } return sum; } int main() { double TDTS; double Tdtg1,Tdtg2,Tdtg3,Tdtg4; char str[100]; double time; unsigned int frequency; bzero(str,sizeof(str)); printf("1s = 1000ms \t 1ms = 1000us \t 1us = 1000ns\n"); printf("输入定时器频率(MHZ)\n"); scanf("%d",&frequency); TDTS = (1*1000.0*1000.0*1000.0)/(frequency*1000000.0); printf("TDTS: %0.2lf ns\n",TDTS); sprintf(str,"%0.2lf",TDTS); Tdtg1 = atof(str); printf("Tdtg1:%0.2lf\n",Tdtg1); printf("----------------第一种-------------\n"); double DT1;///持续时间 printf("tTdtg: %lf ns\n",Tdtg1); printf("DTG[7:5]= 0xx => DT=DTG[6:0] × Tdtg1,Tdtg1 = TDTS\n"); printf("Tdtg1: %0.2lf ns\n",Tdtg1); DT1 = (pow(2,7)-1)*Tdtg1; printf("0--(2^(7)-1)*Tdtg1 :\n DT1 = 0ns ~~~~~%0.2lf ns\n",DT1); printf("----------------第二种-------------\n"); double DT2_0,DT2_1;///持续时间 Tdtg2 = atof(str)*2; printf("Tdtg2 = TDTS*2: %0.2lf ns\n",Tdtg2); printf("DTG[7:5]=10x => DT=(64+DTG[5:0])Tdtg2 , Tdtg2 = 2×TDTS\n"); DT2_0 = 64*Tdtg2; DT2_1 = (64+(pow(2,6)-1))*Tdtg2; printf("(64 + 0 ~ 64 + 2 ^ 6 - 1)*2* Tdtg2:\n DT2 =%0.2lf ns~~~%0.2lf ns\n",DT2_0,DT2_1); printf("----------------第三种-------------\n"); double DT3_0,DT3_1;///持续时间 Tdtg3 = atof(str)*8; printf("Tdtg3 = TDTS*8: %0.2lf ns\n",Tdtg3); DT3_0 = 32*Tdtg3; DT3_1 = (32+(pow(2,5)-1))*Tdtg3; printf("DTG[7:5]=110 => DT=(32+DTG[4:0]) × Tdtg3,Tdtg3 = 8 × TDTS\n"); printf("(32 + 0 ~ 32 + 2 ^ 5 - 1)*2* Tdtg3:\n DT3 =%0.2lf ns~~~%0.2lf ns\n",DT3_0,DT3_1); printf("----------------第四种-------------\n"); double DT4_0,DT4_1;///持续时间 Tdtg4 = atof(str)*16; printf("Tdtg4 = TDTS*16: %0.2lf ns\n",Tdtg4); DT4_0 = 32*Tdtg4; DT4_1 = (32+(pow(2,5)-1))*Tdtg4; printf("DTG[7:5]=110 =16> DT=(32+DTG[4:0]) × Tdtg4,Tdtg4 = 8 × TDTS\n"); printf("(32+0~32+ 2^4 - 1)*2* Tdtg4: \n DT4 =%0.2lf ns~~~%0.2lf ns\n",DT4_0,DT4_1); printf("输入你需要死区时间(ns)--尽量选在区域内的范围的死区时间\n"); scanf("%lf",&time); double ret = 0; int result = 0; if(time ==DT1 || time < DT1) { DTG[7]=0; printf("属于第一情况:最高永远为 0 \n"); printf("DT1:%0.2lf\n",Tdtg1); ret = time / Tdtg1+0.5; ////四舍五入 printf("time / Tdtg1 =%0.0lf\n",ret); result = dectobin(ret); printf("位数不够7位时,在给寄存器赋值时要自已在前面手动补0----DTG[6:0]\n");
printf("DTG[6:0]:%d\n",result);
printf("DTG[7:0]:0b0 %d\n",result);
return 0;
}
if((time >DT2_0 && time < DT2_1) || time == DT2_0 || time == DT2_1)
{
DTG[0]=1;DTG[1]=1;
printf("属于第二情况:DTG[7:6]永远为 10 \n");
printf("DT1:%0.2lf\n",Tdtg2);
ret = time / Tdtg2 - 64+0.5; ////四舍五入
printf("time / Tdtg2 =%0.0lf\n",ret);
result =dectobin(ret);
printf("位数不够6位时,在给寄存器赋值时要自已在前面手动补0----DTG[5:0]\n");
printf("DTG[5:0]:%d\n",result);
printf("DTG[7:0]:0b10 %d\n",result);
return 0;
}
if((time >DT3_0 && time < DT3_1 )|| time == DT3_0 || time == DT3_1)
{
DTG[0]=1;DTG[1]=1;DTG[2]=0;
printf("属于第三情况:DTG[7:5]永远为 110 \n");
printf("DT1:%0.2lf\n",Tdtg3);
ret = time / Tdtg3 - 32+0.5; ////四舍五入
printf("time / Tdtg3 =%0.0lf\n",ret);
result =dectobin(ret);
printf("位数不够5位时,在给寄存器赋值时要自已在前面手动补0----DTG[4:0]\n");
printf("DTG[4:0]:%d\n",result);
printf("DTG[7:0]:0b110 %d\n",result);
return 0;
}
if((time >DT4_0 && time < DT4_1 )|| time == DT4_0 || time == DT4_1)
{
DTG[0]=1;DTG[1]=1;DTG[2]=1;
printf("属于第四情况:DTG[7:5]永远为 111 \n");
printf("DT1:%0.2lf\n",Tdtg4);
ret = time / Tdtg4 - 32+0.5; ////四舍五入
printf("time / Tdtg4 =%0.0lf\n",ret);
result =dectobin(ret);
printf("位数不够5位时,在给寄存器赋值时要自已在前面手动补0----DTG[4:0]\n");
printf("DTG[4:0]:%d\n",result);
printf("DTG[7:0]:0b110 %d\n",result);
}
return 0;
}
## 本次代码实现有些瑕疵,
**例如图片上第三种情况:** 定时器频率:72Mhz 死区时间:5000ns
## 这里的DTG[4:0]应该是 01101;DTG[7:0]应该是0b110 01101;
## 有能力者可以帮我完善一下也行!哈哈哈!## 有错误请指出