2017 Multi-University Training Contest - Team 10
rank 71
1002 Array Challenge
BM算法
#include <bits/stdc++.h> using namespace std; #define rep(i,a,n) for (int i=a;i<n;i++) #define per(i,a,n) for (int i=n-1;i>=a;i--) #define pb push_back #define mp make_pair #define all(x) (x).begin(),(x).end() #define fi first #define se second #define SZ(x) ((int)(x).size()) typedef long long ll; typedef vector<ll> VI; typedef pair<int,int> PII; const ll mod=1000000007; ll powmod(ll a,ll b) {ll res=1; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;} // head int _; namespace linear_seq { const int N=10010; ll res[N],base[N],_c[N],_md[N]; vector<int> Md; void mul(ll *a,ll *b,int k) { rep(i,0,k+k) _c[i]=0; rep(i,0,k) if (a[i]) rep(j,0,k) _c[i+j]=(_c[i+j]+a[i]*b[j])%mod; for (int i=k+k-1;i>=k;i--) if (_c[i]) rep(j,0,SZ(Md)) _c[i-k+Md[j]]=(_c[i-k+Md[j]]-_c[i]*_md[Md[j]])%mod; rep(i,0,k) a[i]=_c[i]; } int solve(ll n,VI a,VI b) { // a 系数 b 初值 b[n+1]=a[0]*b[n]+... // printf("%d\n",SZ(b)); ll ans=0,pnt=0; int k=SZ(a); assert(SZ(a)==SZ(b)); rep(i,0,k) _md[k-1-i]=-a[i];_md[k]=1; Md.clear(); rep(i,0,k) if (_md[i]!=0) Md.push_back(i); rep(i,0,k) res[i]=base[i]=0; res[0]=1; while ((1ll<<pnt)<=n) pnt++; for (int p=pnt;p>=0;p--) { mul(res,res,k); if ((n>>p)&1) { for (int i=k-1;i>=0;i--) res[i+1]=res[i];res[0]=0; rep(j,0,SZ(Md)) res[Md[j]]=(res[Md[j]]-res[k]*_md[Md[j]])%mod; } } rep(i,0,k) ans=(ans+res[i]*b[i])%mod; if (ans<0) ans+=mod; return ans; } VI BM(VI s) { VI C(1,1),B(1,1); int L=0,m=1,b=1; rep(n,0,SZ(s)) { ll d=0; rep(i,0,L+1) d=(d+(ll)C[i]*s[n-i])%mod; if (d==0) ++m; else if (2*L<=n) { VI T=C; ll c=mod-d*powmod(b,mod-2)%mod; while (SZ(C)<SZ(B)+m) C.pb(0); rep(i,0,SZ(B)) C[i+m]=(C[i+m]+c*B[i])%mod; L=n+1-L; B=T; b=d; m=1; } else { ll c=mod-d*powmod(b,mod-2)%mod; while (SZ(C)<SZ(B)+m) C.pb(0); rep(i,0,SZ(B)) C[i+m]=(C[i+m]+c*B[i])%mod; ++m; } } return C; } int gao(VI a,ll n) { VI c=BM(a); c.erase(c.begin()); rep(i,0,SZ(c)) c[i]=(mod-c[i])%mod; return solve(n,c,VI(a.begin(),a.begin()+SZ(c))); } }; ll b,a; ll bb[20],aa[20],h[20]; ll n; vector<ll>vec; int main() { // freopen("data.out","w",stdout); h[0]=2;h[1]=3;h[2]=6; for(int i=3;i<=11;i++) { h[i]=(4*h[i-1]+17*h[i-2]-12*h[i-3]-16); } for(int i=2;i<=10;i++) { bb[i]=(3*h[i+1]*h[i]+9*h[i+1]*h[i-1]+9*h[i]*h[i]+27*h[i]*h[i-1]-18*h[i+1]-126*h[i]-81*h[i-1]+192)+(1LL<<(2*i)); ll tmp=(ll)(sqrt(bb[i]))%mod; vec.push_back(tmp); } for (scanf("%d",&_);_;_--) { scanf("%I64d",&n); b=linear_seq::gao(vec,n-2); printf("%I64d\n",b%mod); } }
1008 Monkeys
二二猴子配对
#include <bits/stdc++.h> const long long mod = 1e9+7; const double ex = 1e-10; #define inf 0x3f3f3f3f using namespace std; namespace fastIO{ #define BUF_SIZE 100000 #define OUT_SIZE 100000 #define ll long long //fread->read bool IOerror=0; inline char nc(){ static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE; if (p1==pend){ p1=buf; pend=buf+fread(buf,1,BUF_SIZE,stdin); if (pend==p1){IOerror=1;return -1;} //{printf("IO error!\n");system("pause");for (;;);exit(0);} } return *p1++; } inline bool blank(char ch){return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';} inline int read(int &x){ bool sign=0; char ch=nc(); x=0; for (;blank(ch);ch=nc()); if (IOerror)return 0; if (ch=='-')sign=1,ch=nc(); for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; if (sign)x=-x; return 1; } inline int read(ll &x){ bool sign=0; char ch=nc(); x=0; for (;blank(ch);ch=nc()); if (IOerror)return 0; if (ch=='-')sign=1,ch=nc(); for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; if (sign)x=-x; return 1; } inline int read(double &x){ bool sign=0; char ch=nc(); x=0; for (;blank(ch);ch=nc()); if (IOerror)return 0; if (ch=='-')sign=1,ch=nc(); for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; if (ch=='.'){ double tmp=1; ch=nc(); for (;ch>='0'&&ch<='9';ch=nc())tmp/=10.0,x+=tmp*(ch-'0'); } if (sign)x=-x; return 1; } inline int read(char *s){ char ch=nc(); for (;blank(ch);ch=nc()); if (IOerror)return 0; for (;!blank(ch)&&!IOerror;ch=nc())*s++=ch; *s=0; return 1; } inline void read(char &c){ for (c=nc();blank(c);c=nc()); if (IOerror){c=-1;return;} } //fwrite->write struct Ostream_fwrite{ char *buf,*p1,*pend; Ostream_fwrite(){buf=new char[BUF_SIZE];p1=buf;pend=buf+BUF_SIZE;} void out(char ch){ if (p1==pend){ fwrite(buf,1,BUF_SIZE,stdout);p1=buf; } *p1++=ch; } void print(int x){ static char s[15],*s1;s1=s; if (!x)*s1++='0';if (x<0)out('-'),x=-x; while(x)*s1++=x%10+'0',x/=10; while(s1--!=s)out(*s1); } void println(int x){ static char s[15],*s1;s1=s; if (!x)*s1++='0';if (x<0)out('-'),x=-x; while(x)*s1++=x%10+'0',x/=10; while(s1--!=s)out(*s1); out('\n'); } void print(ll x){ static char s[25],*s1;s1=s; if (!x)*s1++='0';if (x<0)out('-'),x=-x; while(x)*s1++=x%10+'0',x/=10; while(s1--!=s)out(*s1); } void println(ll x){ static char s[25],*s1;s1=s; if (!x)*s1++='0';if (x<0)out('-'),x=-x; while(x)*s1++=x%10+'0',x/=10; while(s1--!=s)out(*s1); out('\n'); } void print(double x,int y){ static ll mul[]={1,10,100,1000,10000,100000,1000000,10000000,100000000, 1000000000,10000000000LL,100000000000LL,1000000000000LL,10000000000000LL, 100000000000000LL,1000000000000000LL,10000000000000000LL,100000000000000000LL}; if (x<-1e-12)out('-'),x=-x;x*=mul[y]; ll x1=(ll)floor(x); if (x-floor(x)>=0.5)++x1; ll x2=x1/mul[y],x3=x1-x2*mul[y]; print(x2); if (y>0){out('.'); for (size_t i=1;i<y&&x3*mul[i]<mul[y];out('0'),++i); print(x3);} } void println(double x,int y){print(x,y);out('\n');} void print(char *s){while (*s)out(*s++);} void println(char *s){while (*s)out(*s++);out('\n');} void flush(){if (p1!=buf){fwrite(buf,1,p1-buf,stdout);p1=buf;}} ~Ostream_fwrite(){flush();} }Ostream; inline void print(int x){Ostream.print(x);} inline void println(int x){Ostream.println(x);} inline void print(char x){Ostream.out(x);} inline void println(char x){Ostream.out(x);Ostream.out('\n');} inline void print(ll x){Ostream.print(x);} inline void println(ll x){Ostream.println(x);} inline void print(double x,int y){Ostream.print(x,y);} inline void println(double x,int y){Ostream.println(x,y);} inline void print(char *s){Ostream.print(s);} inline void println(char *s){Ostream.println(s);} inline void println(){Ostream.out('\n');} inline void flush(){Ostream.flush();} }; using namespace fastIO; struct edge{ int to,next; }E[212345]; int head[112345]; int sum[112345]; int nu[112345]; int ans = 0,tot,maxn; int dfs(int u,int f){ int num = 0; for (int i = head[u]; i!=-1 ; i = E[i].next){ int to = E[i].to; if (to == f) continue; if (dfs(to,u) == 0) num++; } if (num>=1){ sum[num+1]++; ans++; maxn = max(maxn,num+1); } nu[u] = num+1; return num; } int main() { int T; read(T); while(T--) { int N,K; int a; ans = 0; read(N); read(K); for (int i = 1;i<=N;i++) head[i] = -1,sum[i] = 0; tot = 0; for (int i = 1; i<N;i++){ read(a); E[tot].next = head[a]; E[tot].to = i+1; head[a] = tot++; E[tot].next = head[i+1]; E[tot].to = a; head[i+1] = tot++; } maxn = 0; dfs(1,0); if (nu[1] == 1){ int to = E[head[1]].to; int num = nu[to]; sum[num]--; sum[num+1]++; } int le = N-K; for (int i = maxn+1; i>=3; i--){ if (sum[i] < le){ le -= sum[i]; ans += sum[i]; sum[i-1] += sum[i]; } else { ans += le; le = 0; break; } } if (le > 0){ ans += (le/2); } print(N-ans); print('\n'); } }
1010 Schedule
贪心
#include <bits/stdc++.h> #define maxn 100010 #define inf 0x3f3f3f3f #define REP(i,x,y) for(int i=x;i<(y);i++) #define RREP(i,x,y) for(int i=x;i>(y);i--) using namespace std; typedef long long ll; typedef pair<int,int> pii; pii t[maxn]; set<pii>S; int ans,n; pii vec[maxn]; int main() { int T;scanf("%d",&T); while(T--) { S.clear();memset(vec,0,sizeof(vec));memset(t,0,sizeof(t)); ans=0;scanf("%d",&n); REP(i,1,n+1) scanf("%d %d",&t[i].first,&t[i].second); sort(t+1,t+1+n); S.insert(make_pair(t[1].second,1)); vec[++ans]=make_pair(t[1].first,t[1].second); REP(i,2,n+1) { auto it=S.upper_bound(make_pair(t[i].first,inf)); if(it!=S.begin()) { it--; int tmp=(*it).second; vec[tmp].second=t[i].second; S.erase(it); S.insert(make_pair(t[i].second,tmp)); } else { vec[++ans]=make_pair(t[i].first,t[i].second); S.insert(make_pair(t[i].second,ans)); } } printf("%d ",ans); ll sum=0; REP(i,1,ans+1) sum+=vec[i].second-vec[i].first; printf("%I64d\n",sum); } }
1011 Two Paths
次短路
#include <iostream> #include <cstdio> #include <cmath> #include <cstring> #include <algorithm> #include <map> #include <queue> #include <stack> #include <vector> #define maxn 100040 #define inf 0x3f3f3f3f3f3f3f3f using namespace std; typedef long long ll; template <class T> inline void read(T &res){ char c;res=0; while((c=getchar())<'0'||c>'9'); while(c>='0'&&c<='9'){ res=res*10+(c-'0'); c=getchar(); } } ////// struct edge{ int to; long long cost; edge(){} edge(int _to,int _cost):to(_to),cost(_cost){} }; vector<edge>e[maxn]; int vis[maxn]; long long dis1[maxn],dis2[maxn]; int flag[maxn]; int pre[maxn]; int n,r; long long spfa(){ queue<int>que;que.push(1); memset(dis1,inf,(n+1) * sizeof (dis1[0])); memset(pre,-1,(n+1) * sizeof (pre[0])); memset(vis,0,(n+1) * sizeof (vis[0])); memset(dis2,inf,(n+1) * sizeof (dis2[0])); memset(flag,0,(n+1) * sizeof (flag[0])); vis[1]=0;dis1[1]=0; while(!que.empty()){ int now=que.front();que.pop(); for(int i=0;i<e[now].size();i++){ int Next=e[now][i].to;int len=e[now][i].cost; if(dis1[Next]>dis1[now]+len){ dis2[Next]=min(dis2[now]+len,dis1[Next]); dis1[Next]=dis1[now]+len; pre[Next] = now; flag[Next] = flag[now]; if(!vis[Next]){ vis[Next]=1;que.push(Next); } } else if(dis1[Next]==dis1[now]+len&&dis2[Next]>dis2[now]+len){ if (pre[Next]!=now) {flag[Next] = 1;pre[Next] = -1;} dis2[Next]=dis2[now]+len; if(!vis[Next]){ vis[Next]=1;que.push(Next); } } else if(dis1[Next]<dis1[now]+len&&dis2[Next]>dis1[now]+len){ dis2[Next]=dis1[now]+len; if(!vis[Next]){ vis[Next]=1;que.push(Next); } } else if (dis1[Next]==dis1[now]+len){ if (pre[Next]!=now) {flag[Next] = 1;pre[Next] = -1;} } } vis[now]=0; } if (flag[n]) return dis1[n]; else return dis2[n]; } int main() { int t; read(t); while (t--){ read(n);read(r); for (int i = 1; i<=n;i++) e[i].clear(); for(int i=1;i<=r;i++) { int u,v,c;read(u),read(v),read(c); e[u].push_back(edge(v,c));e[v].push_back(edge(u,c)); } printf("%lld\n",spfa()); } }
