仅作参考，请指正（都提交通过，但是也有错误，第22题的错误，已经修正）
1、Hello World!
1 #include <stdio.h> 2 int main() 3 { 4 printf("Hello World!"); 5 return 0; 6 }
2、我爱编程
1 #include <stdio.h> 2 int main() 3 { 4 printf("Hello C!\n"); 5 printf("I like programming."); 6 return 0; 7 }
3、计算两个整数的乘积
1 #include <stdio.h> 2 int main() 3 { 4 int a,b; 5 scanf("%d%d",&a,&b); 6 printf("%d",a*b); 7 return 0; 8 }
4、计算圆的面积
1 #include <stdio.h> 2 #include <string.h> 3 #define PI 3.1415 4 int main() 5 { 6 printf("Area=%5.2f\n", PI*4.3*4.3); 7 return 0; 8 }
5、计算平方根
1 #include <stdio.h> 2 #include <math.h> 3 int main() 4 { 5 double x; 6 scanf("%lf", &x); 7 printf("%f\n", sqrt(x)); 8 return 0; 9 }
6、输出逆序数
1 #include <stdio.h> 2 #include <string.h> 3 #include <math.h> 4 int main() 5 { 6 int x,y = 0; 7 scanf("%d", &x); 8 while(x) 9 { 10 y = y*10 + x%10; 11 x /= 10; 12 } 13 printf("y=%d\n", y); 14 return 0; 15 }
7、交换两个变量
1 #include<stdio.h> 2 #include<math.h> 3 4 int main() 5 { 6 int a,b,t; 7 scanf("%d,%d",&a,&b); 8 t = a; 9 a = b; 10 b = t; 11 printf("%d,%d",a,b); 12 return 0; 13 }
8、输出字符ASCII码
1 #include<stdio.h> 2 #include<math.h> 3 4 int main() 5 { 6 int a; 7 a = getchar(); 8 printf("ASCII=%d",a); 9 return 0; 10 }
9、求一元二次方程的两个实根
1 #include<stdio.h> 2 #include<math.h> 3 4 int main() 5 { 6 float x1,x2; 7 x1 = (-1 + sqrt(1+4*2))/2.0; 8 x2 = (-1 - sqrt(1+4*2))/2.0; 9 printf("x1=%.4f\n",x1); 10 printf("x2=%.4f\n",x2); 11 return 0; 12 }
10、计算银行存款本息
1 #include<stdio.h> 2 #include<math.h> 3 4 int main() 5 { 6 int money,year; 7 double rate,sum = 0; 8 scanf("%d%d%lf",&money,&year,&rate); 9 sum = money*pow((1+rate),year); 10 11 printf("sum=%7.2f",sum); 12 return 0; 13 }
11、大小写字母转换
1 #include <stdio.h> 2 #include <stdio.h> 3 #include <stdlib.h> 4 5 int main() 6 { 7 char ch; 8 ch = getchar(); 9 if(ch>='a'&&ch<='z') 10 ch -= 32; 11 else 12 ch += 32; 13 putchar(ch); 14 return 0; 15 }
12、计算分段函数
1 #include <stdio.h> 2 int main(void) 3 { 4 double x, y; 5 scanf("%lf",&x); 6 if ( x<0 ) 7 y=0; 8 else if( x<=15 ) 9 y=4*x/3; 10 else 11 y=2.5*x-10.5; 12 printf("y=%.2f",y); 13 return 0; 14 }
13、百分制成绩转换为五级分制成绩
1 #include <stdio.h> 2 #include <stdio.h> 3 #include <stdlib.h> 4 5 int main() 6 { 7 float achievment; 8 scanf("%f",&achievment); 9 10 int a = achievment; 11 char ch; 12 13 switch(a/10){ 14 case 10: 15 case 9:ch = 'A';break; 16 case 8:ch = 'B';break; 17 case 7:ch = 'C';break; 18 case 6:ch = 'D';break; 19 default:ch = 'E'; 20 } 21 printf("grade:%c\n",ch); 22 23 return 0; 24 }
14、输出水仙花数
1 #include <stdio.h> 2 #include <stdio.h> 3 #include <stdlib.h> 4 5 int main() 6 { 7 int i; 8 scanf("%d",&i); 9 10 int a = i%10, b = i/10%10, c = i/100; 11 if(a*a*a + b*b*b + c*c*c == i) 12 printf("%d是水仙花数！",i); 13 else 14 printf("%d不是水仙花数！",i); 15 16 return 0; 17 }
15、用for语句实现判断并求和
1 #include<stdio.h> 2 3 int main() 4 { 5 int sum = 0; 6 for(int i=1; i<=100; ++i) 7 { 8 if(i%3==0 && i%5==1) 9 sum += i; 10 } 11 printf("sum=%d",sum); 12 13 return 0; 14 }
16、用do while 语句实现从键盘输入一组整数，求平均值
1 #include<stdio.h> 2 3 int main() 4 { 5 int i=0, x; 6 float sum = 0; 7 do{ 8 scanf("%d",&x); 9 if(x<0) break; 10 sum += x; 11 i++; 12 }while(x>=0); 13 printf("AVE=%.2f\n",sum/i); 14 return 0; 15 }
17、用while语句实现计算圆周率 pi (3.14) 的近似值
1 #include<stdio.h> 2 #include <math.h> 3 #define EPS 1e-5 4 int main() 5 { 6 float pi = 0, sign = 1, x = 1; 7 8 while(fabs(sign/x) > EPS) 9 { 10 pi += sign/x; 11 x += 2; 12 sign = -sign; 13 } 14 printf("pi=%.2f\n",pi*4); 15 return 0; 16 }
18、求两个整数的最大公约数
1 #include<stdio.h> 2 #include<stdlib.h> 3 4 int GCD(int x, int y); 5 int main() 6 { 7 int a,b; 8 scanf("%d%d",&a,&b); 9 printf("GCD=%d\n",GCD(a,b)); 10 return 0; 11 } 12 13 int GCD(int x, int y){ 14 return y == 0 ? x : GCD(y, x%y); 15 }
19、找素数
1 #include<stdio.h> 2 #include<stdlib.h> 3 4 int isPrime(int x); 5 int main() 6 { 7 int a; 8 scanf("%d",&a); 9 for(int i=a+1;;++i){ 10 if(isPrime(i)){ 11 printf("prime=%d\n",i); 12 break; 13 } 14 } 15 return 0; 16 } 17 18 int isPrime(int x){ 19 for(int i=2; i<x; ++i) 20 if(x%i==0) 21 return 0; 22 return 1; 23 }
20、斐波那契数列求和
1 #include<stdio.h> 2 #include<stdlib.h> 3 4 int main() 5 { 6 int sum = 0, a=1,b=1; 7 for(int i=0;i<20;i+=2){ 8 sum += a+b; 9 a = a+b; 10 b = a+b; 11 } 12 printf("sum=%d\n",sum); 13 return 0; 14 }
21、逆序存放数据
1 #include<stdio.h> 2 #define N 100 3 int main() 4 { 5 int arr[N] = {0}, n=6; 6 for(int i=n-1; i>=0; --i) 7 scanf("%d",&arr[i]); 8 for(int j=0; j<n; ++j) 9 printf("%d\n",arr[j]); 10 return 0; 11 }
22、找出一维整型数组中的次最大值
#include<stdio.h> #define N 5 /*设次大值一定存在*/ int main() { int i, j, arr[N+1] = {0}; /* 输入5个数 */ for(i=0; i<N; ++i) scanf("%d",&arr[i]); /* 冒泡排序 */ for(i=0; i<N-1; ++i) for(j=0; j<N-i-1; ++j) if(arr[j]<arr[j+1]){ int t = arr[j]; arr[j] = arr[j+1]; arr[j+1] = t; } /* 求次最大值下标i*/ for(i=1; arr[0]==arr[i] && i<N; ++i) ; /*if(i==N) printf("次大值不存在!\n");*/ printf("次最大值=%d",arr[i]); return 0; }
/* 求最大值、次大值可以不用排序 */ #include <stdio.h> #define N 5 int main() { int i, arr[N] = {0}; int max1, max2; scanf("%d%d",&arr[0],&arr[1]); max1 = max2 = arr[0]; arr[1] > max1 ? (max1 = arr[1]) : (max2 = arr[1]); for(i=2; i<N; ++i){ scanf("%d",&arr[i]); if(arr[i]>max1){ max2 = max1; max1 = arr[i]; } else if(arr[i]>max2){ max2 = arr[i]; } } /*if(max1==max2) printf("次大值不存在!\n"); else printf("次最大值=%d",max2);*/ /*次最大值 max2 是存在的 */ printf("次最大值=%d",max2); return 0; }
#include <stdio.h> #include <limits.h> #define N 5 int main() { int i, arr[N] = {0}; int max1, max2; max1 = max2 = INT_MIN; for(i=0; i<N; ++i){ scanf("%d",&arr[i]); if(arr[i]>max1){ max2 = max1; max1 = arr[i]; } else if(arr[i]>max2){ max2 = arr[i]; } } /* 次最大值 max2 */ if(max1 == INT_MIN) printf("次大值不存在!\n"); else printf("次最大值=%d",max2); return 0; }
23、调整最大值的位置
1 #include<stdio.h> 2 #define N 100 3 int main() 4 { 5 int arr[N] = {0}, n=6, max=0, maxi=0; 6 scanf("%d",&arr[0]); 7 max=arr[0]; 8 9 for(int i=1; i<n; ++i){ 10 scanf("%d",&arr[i]); 11 if(arr[i]>max){ 12 max = arr[i]; 13 maxi = i; 14 } 15 16 } 17 int t = arr[n-1]; 18 arr[n-1] = arr[maxi]; 19 arr[maxi] = t; 20 21 for(int j=0; j<n; ++j) 22 printf("%d\n",arr[j]); 23 return 0; 24 }
24、连接两个字符串
1 #include<stdio.h> 2 #include<string.h> 3 #define N 100 4 int main() 5 { 6 char a[2*N] = "", b[N] = ""; 7 scanf("%s%s",a,b); 8 /* strcpy(&a[strlen(a)],b);//没有用strcat用的strcpy 9 */ 10 //不用函数 11 int i; 12 for(i=0; a[i]; ++i);//求字符串'\0'下标 13 char *p = a+i, *q = b; 14 while(*q) 15 { 16 *p++ = *q++; 17 } 18 *p = '\0'; 19 20 printf("%s\n",a); 21 return 0; 22 }
1 #include<stdio.h> 2 #include<string.h> 3 #define N 100 4 int main() 5 { 6 char a[2*N] = "", b[N] = ""; 7 scanf("%s%s",a,b); 8 9 char *p = a, *q = b; 10 while(*p) p++; 11 while((*p++=*q++)!='\0'); 12 13 printf("%s\n",a); 14 return 0; 15 }
25、求矩阵外围元素之和
1 #include <stdio.h> 2 #include <malloc.h> 3 int main() 4 { 5 int sum=0, n=3; 6 int *arr = (int*)malloc(sizeof(int)*n*n); //一维模拟二维数组 7 8 for(int i=0; i<n*n; ++i) 9 { 10 scanf("%d",&arr[i]); 11 } 12 13 for(int i=0; i<n; ++i) 14 { 15 for(int j=0; j<n; ++j) 16 { 17 if(i==0||i==n-1 || j==0|| j==n-1 ) 18 { 19 sum += arr[i*n+j]; //一行n个 20 } 21 } 22 } 23 24 printf("%d",sum); 25 26 return 0; 27 }
26、求矩阵主对角线和副对角线元素之和
1 #include <stdio.h> 2 #define N 5 3 int main() 4 { 5 char str[N][N]; 6 int i,j,sum=0; 7 8 for(i=0; i<N; ++i) 9 for(j=0; j<N; ++j) 10 scanf("%d",&str[i][j]); 11 12 for(i=0; i<N; ++i) 13 for(j=0; j<N; ++j) 14 { 15 if(i==j) 16 sum += str[i][j]; 17 if(i==N-j-1) 18 sum += str[i][j]; 19 } 20 printf("sum=%d\n",sum); 21 return 0; 22 }
27、将字符串的小写字母转换为大写字母
1 #include <stdio.h> 2 #define N 1000 3 int main() 4 { 5 char str[N]=""; 6 int i=0; 7 gets(str); 8 9 while(str[i]){ 10 if(str[i]>='a'&&str[i]<='z') 11 str[i] -= 32; 12 i++; 13 } 14 printf("%s\n",str); 15 return 0; 16 }
28、编写函数，计算银行存款本息并输出
1 #include <stdio.h> 2 #include <stdlib.h> 3 double fun(int money,int year, double rate) 4 { 5 double sum = money; 6 while(year--){ 7 sum = sum*(1+rate); 8 } 9 return sum; 10 } 11 int main() 12 { 13 int money, year; 14 double rate, sum=0; 15 scanf("%d%d%lf",&money,&year,&rate); 16 sum = fun(money,year,rate); 17 printf("sum=%.2f",sum); 18 return 0; 19 }
29、数值转换
1 /*位运算*/ 2 #include <stdio.h> 3 void fun(int x) 4 { 5 int j=31;/*按32位定义*/ 6 while(!((x&(1<<j))>>j))/*去前面的0*/ 7 j--; 8 for(; j>=0; j--)/*按位输出*/ 9 printf("%d", (x&(1<<j))>>j); 10 } 11 int main() 12 { 13 int x; 14 scanf("%d",&x); 15 fun(x); 16 return 0; 17 }
30、求一组数中大于平均值的数的个数
1 #include <stdio.h> 2 #define N 100 3 4 int main() 5 { 6 int num[N] = {0},count=0; 7 double sum = 0; 8 for(int i=0; i<10; ++i){ 9 scanf("%d",&num[i]); 10 sum += num[i]; 11 } 12 for(int j=0; j<10; ++j) 13 if(num[j]>sum/10) 14 count++; 15 printf("%d",count); 16 return 0; 17 }
31、求x的n次方
1 #include <stdio.h> 2 double cube(double x,int n) 3 { 4 if(n ==1) 5 return x; 6 else 7 return x*cube(x,n-1); 8 } 9 int main() 10 { 11 double x,y; 12 int n; 13 scanf("%lf%d",&x,&n); 14 y=cube(x,n); 15 printf("%f",y); 16 return 0; 17 }
32、输出最大、最小数
1 #include <stdio.h> 2 void fun(int *arr,int *max,int *min){ 3 *max = *min = arr[0]; 4 for(int i=1; i<10; ++i){ 5 if(arr[i]>*max) 6 *max = arr[i]; 7 if(arr[i]<*min) 8 *min = arr[i]; 9 } 10 } 11 int main() 12 { 13 int max,min; 14 int arr[10] = {0}; 15 for(int i=0; i<10; ++i){ 16 scanf("%d",&arr[i]); 17 } 18 fun(arr,&max,&min); 19 printf("max=%d,min=%d",max,min); 20 return 0; 21 }
33、任意整数转换为千分位分隔的字符形式
1 #include <stdio.h> 2 #define N 100 3 int main() 4 { 5 int n; 6 scanf("%d",&n); 7 int arr[N] = {0},index = 0; 8 while(n) 9 { 10 arr[index++] = n%10; 11 n /= 10; 12 } 13 for(int i=index-1; i>=0; --i) 14 { 15 printf("%d",arr[i]); 16 if(i%3==0&&i) 17 printf(","); 18 } 19 return 0; 20 }
34、利用指针编写程序，统计字符串的长度
1 #include <stdio.h> 2 #define N 100 3 int main() 4 { 5 char str[N] = ""; 6 gets(str); 7 char *p = str; 8 int len = 0; 9 while(*p) 10 { 11 len++; 12 p++; 13 } 14 printf("Length of the string is %d\n",len); 15 return 0; 16 }
35、利用指针编程，将数组中所有元素的值对称交换
1 #include <stdio.h> 2 #define N 10 3 int main() 4 { 5 int arr[N] = {0}; 6 for(int i=0; i<N; ++i) 7 scanf("%d",&arr[i]); 8 int *p = arr, *q = arr+N-1; 9 while(p<q) 10 { 11 int t = *p; 12 *p = *q; 13 *q = t; 14 p++, q--; 15 } 16 for(int j=0; j<N; ++j) 17 printf("%2d",arr[j]); 18 return 0; 19 }
36、利用指针编写程序，求一维数组中的最大和最小的元素值
1 #include <stdio.h> 2 #define N 10 3 int main() 4 { 5 int arr[N] = {0}; 6 for(int i=0; i<N; ++i) 7 scanf("%d",&arr[i]); 8 int max, min; 9 max = min = arr[0]; 10 for(int j=1; j<N; ++j) 11 { 12 if(arr[j]>max) 13 max = arr[j]; 14 if(arr[j]<min) 15 min = arr[j]; 16 } 17 printf("max=%d,min=%d",max,min); 18 return 0; 19 }
37、利用指针编写一函数，输入3个整数，按由大到小的顺序将它们输出
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <string.h> 4 #define N 256 5 6 void swap(int *a, int *b) 7 { 8 int t = *a; 9 *a = *b; 10 *b = t; 11 } 12 int main( ) 13 { 14 int arr[N] = {0}; 15 for(int i=0; i<3; ++i) 16 scanf("%d",&arr[i]); 17 if(arr[0]<arr[1]) 18 swap(&arr[0],&arr[1]); 19 if(arr[0]<arr[2]) 20 swap(&arr[0],&arr[2]); 21 if(arr[1]<arr[2]) 22 swap(&arr[1],&arr[2]); 23 for(int j=0;j<3; ++j) 24 printf("%3d",arr[j]); 25 return 0; 26 }
38、用指向数组的指针变量实现输出指定学生的全部成绩
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <string.h> 4 #define N 256 5 6 int main( ) 7 { 8 float score[][4]={{60,70,80,90},{56,89,67,88},{34,78,90,66}}; 9 float (*p)[4] = score; 10 int n; 11 scanf("%d",&n); 12 for(int i=0;i<4;++i) 13 printf("%8.2f",p[n][i]); 14 return 0; 15 }
39、某班有5名同学，建立一个学生的简单信息表，包括学号、姓名、3门课程的成绩，编写程序，计算每名学生的平均成绩及名次
1 /* 2 测试数据 3 201701 zhao 29.8 85.4 65.4 4 201702 qian 96.5 87.5 65.4 5 201703 sun 85.4 65.4 84.6 6 201704 li 63.4 95.4 86.3 7 201705 zhou 65.9 84.6 97.5 8 */ 9 #include<stdio.h> 10 11 struct student{ 12 long no; 13 char name[20]; 14 float score[3]; 15 }stu[5],*p; 16 17 int rank(float *ave, float score){ 18 int rank = 5; 19 for(int i=0; i<5; ++i) 20 if(ave[i]<score) 21 rank--; 22 return rank; 23 } 24 25 int main() 26 { 27 float ave[5] = {0.0}; 28 int index = 0; 29 for(p=stu; p<stu+5; ++p){ //stu+5 30 scanf("%ld %s %f %f %f", 31 &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]); 32 ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0; 33 } 34 35 printf("Number: Name: score: Average： rank:\n"); 36 for(index=0,p=stu; p<stu+5; ++p){ 37 printf("%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n", 38 p->no,p->name,p->score[0],p->score[1], 39 p->score[2],ave[index++],rank(ave,ave[index])); 40 } 41 return 0; 42 }
40、某班有10名同学，建立学生结构体类型，包括学号、姓名、3门课程的成绩，编写程序，读入已准备好的文本文件student1.txt，为结构体数组变量赋值，计算每名学生的平均成绩及名次。结果输出到屏幕的同时保存到student2.txt文件中
1 #include <stdio.h> 2 3 /* 结构体定义 */ 4 struct student{ 5 long no; 6 char name[20]; 7 float score[3]; 8 }stu[10],*p; 9 10 /* 计算名次 */ 11 int rank(float *ave, float score, int n){ 12 int rank = n; 13 for(int i=0; i<n; ++i) 14 if(ave[i]<score) 15 rank--; 16 return rank; 17 } 18 19 int main() 20 { 21 /* 打开文件 */ 22 FILE *fp1,*fp2; 23 fp1 = fopen("student1.txt","r"); 24 fp2 = fopen("student2.txt","w"); 25 26 /* 读取数据 计算平均值 */ 27 float ave[10] = {0.0}; 28 int index = 0; 29 for(p=stu; p<stu+10; ++p){ //stu+10 30 fscanf(fp1,"%ld %s %f %f %f", 31 &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]); 32 ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0; 33 } 34 /* 写入文件 */ 35 for(index = 0,p=stu; p<stu+10; ++p){ 36 fprintf(fp2,"%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n", 37 p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index],10)); 38 } 39 /* 关闭文件 */ 40 fclose(fp1); 41 fclose(fp2); 42 return 0; 43 }
1 测试数据 student1.txt 2 201701 zhao 29.8 85.4 65.4 3 201702 qian 96.5 87.5 65.4 4 201703 sun 85.4 65.4 84.6 5 201704 li 63.4 95.4 86.3 6 201705 zhou 65.9 84.6 97.5 7 201706 wu 39.8 85.4 75.4 8 201707 zheng 96.5 82.5 75.9 9 201708 wang 75.4 85.4 94.6 10 201709 feng 73.4 95.4 56.3 11 2017010 chen 75.9 74.6 77.5
1 /* 2 测试数据 student1.txt 3 201701 zhao 29.8 85.4 65.4 4 201702 qian 96.5 87.5 65.4 5 201703 sun 85.4 65.4 84.6 6 201704 li 63.4 95.4 86.3 7 201705 zhou 65.9 84.6 97.5 8 201706 wu 39.8 85.4 75.4 9 201707 zheng 96.5 82.5 75.9 10 201708 wang 75.4 85.4 94.6 11 201709 feng 73.4 95.4 56.3 12 2017010 chen 75.9 74.6 77.5 13 */ 14 #include <stdio.h> 15 struct student{ 16 long no; 17 char name[20]; 18 float score[3]; 19 }stu[10],*p; 20 21 int rank(float *ave, float score){ 22 int rank = 10; 23 for(int i=0; i<10; ++i) 24 if(ave[i]<score) 25 rank--; 26 return rank; 27 } 28 29 int main() 30 { 31 FILE *fp; 32 fp = fopen("d:\\student1.txt","r"); 33 float ave[10] = {0.0}; 34 int index = 0; 35 for(p=stu; p<stu+10; ++p){ //stu+10 36 fscanf(fp,"%ld %s %f %f %f", 37 &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]); 38 ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0; 39 } 40 printf("Number: Name: score: Average： rank:\n"); 41 for(index = 0, p=stu; p<stu+10; ++p){ 42 printf("%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n", 43 p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index])); 44 } 45 fclose(fp); 46 /* ---------------------------------------------- */ 47 fp = fopen("d:\\student2.txt","w"); 48 for(index = 0, p=stu; p<stu+10; ++p){ 49 fprintf(fp,"%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n", 50 p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index])); 51 } 52 fclose(fp); 53 return 0; 54 }
41、输入并保存5名职工的信息，计算并输出平均工资，再按照工资从高到低的顺序输出
1 #include <stdio.h> 2 #include <stdlib.h> 3 typedef struct employee EMPLOYEE; 4 struct employee{ 5 int no; 6 char name[10]; 7 double salary; 8 }; 9 int compare(const void * a,const void *b)/*比较函数*/ 10 { 11 return (*(EMPLOYEE*)a).salary < (*(EMPLOYEE*)b).salary; 12 } 13 14 int main() 15 { 16 double sum = 0; 17 EMPLOYEE e[5]; 18 for(int i=0; i<5; ++i){ 19 scanf("%d%s%lf",&e[i].no,e[i].name,&e[i].salary); 20 sum += e[i].salary; 21 } 22 qsort(e,5,sizeof(EMPLOYEE),compare); 23 printf("The Average=%-6.1f\n",sum/5); 24 for(int i=0; i<5; ++i){ 25 printf("%-10d%-10s%-6.1f\n",e[i].no,e[i].name,e[i].salary); 26 } 27 return 0; 28 }
1 #include <stdio.h> 2 typedef struct employee EMPLOYEE; 3 struct employee{ 4 int no; 5 char name[10]; 6 double salary; 7 }; 8 /* 选择排序 */ 9 void sortSalary(EMPLOYEE e[]){ 10 for(int i=0; i<5-1; ++i) 11 for(int j=i+1; j<5; ++j) 12 if(e[i].salary<e[j].salary) 13 { 14 EMPLOYEE t = e[i]; 15 e[i] = e[j]; 16 e[j] = t; 17 } 18 } 19 20 int main() 21 { 22 double sum = 0; 23 EMPLOYEE e[5]; 24 for(int i=0; i<5; ++i){ 25 scanf("%d%s%lf",&e[i].no,e[i].name,&e[i].salary); 26 sum += e[i].salary; 27 } 28 sortSalary(e); 29 printf("The Average=%-6.1f\n",sum/5); 30 for(int i=0; i<5; ++i){ 31 printf("%-10d%-10s%-6.1f\n",e[i].no,e[i].name,e[i].salary); 32 } 33 return 0; 34 }
1 测试数据 2 19610901 zhao 8524 3 20170205 qian 6605 4 20100320 sun 6750 5 19730205 wang 8230 6 19800725 zhou 7590
42、编写程序键盘输入整型变量n，从低位开始取出整型变量n偶数位上的数依次放在整型变量s中，然后输出s
1 #include<stdio.h> 2 3 int main() 4 { 5 int n; 6 scanf("%d",&n); 7 int s=0,i=1; 8 while(n) 9 { 10 n/=10; 11 s += n%10*i; 12 i *= 10; 13 n/=10; 14 } 15 printf("%d",s); 16 return 0; 17 }
1 #include <stdio.h> 2 #define N 100 3 int main() 4 { 5 int n,s=0,i=1;//n的偶数位依次放在s中 6 scanf("%d",&n); 7 while(n>10)//确保不取奇数位 8 { 9 s += i*(n/10%10); //取偶数位累加 10 n /= 100; //去两位 11 i *= 10; //升位 12 } 13 printf("%d\n",s); 14 return 0; 15 }
1 #include <stdio.h> 2 #define N 100 3 int main() 4 { 5 int s; 6 scanf("%d",&s); 7 8 int arr[N] = {0}; 9 int i=0; 10 while(s>10) 11 { 12 arr[i++] = s/10%10; 13 s /= 100; 14 } 15 for(int j=i-1; j>=0; --j) 16 printf("%d",arr[j]); 17 return 0; 18 }
其他课程相关
1、字符串a下标值为偶数的元素由小到大排序，其他元素不变
1 #include<stdio.h> 2 int main() 3 { 4 char a[]="labchmfye",t; 5 int len = 9; 6 7 int i,j; 8 for(i=0;i<len-2;i+=2) 9 { 10 for(j=i+2;j<len; j+=2){ 11 if(a[i]>a[j]) 12 { 13 t=a[i]; 14 a[i]=a[j]; 15 a[j]=t; 16 } 17 } 18 } 19 puts(a); 20 printf("\n"); 21 return 0; 22 }
2、十进制正整数转换为二进制1
1 /*位运算*/ 2 #include <stdio.h> 3 void fun(int x) 4 { 5 int j=31;/*按32位定义*/ 6 while(!((x&(1<<j))>>j))/*去前面的0*/ 7 j--; 8 for(; j>=0; j--)/*按位输出*/ 9 printf("%d", (x&(1<<j))>>j); 10 } 11 int main() 12 { 13 int x; 14 scanf("%d",&x); 15 fun(x); 16 return 0; 17 }
3、十进制正整数转换为二进制2
1 #include <stdio.h> 2 #define N 100 3 void fun(int n, int base) 4 { 5 int num[N] = {0}, i=0; 6 while(n) 7 { 8 num[i++] = n%base; 9 n /= base; 10 } 11 for(int j=i-1;j>=0; --j) 12 printf("%d",num[j]); 13 } 14 int main() 15 { 16 int n; 17 scanf("%d",&n); 18 fun(n,2); 19 return 0; 20 }
4、螺旋二维数组
1 #include<stdio.h> 2 int main() 3 { /* 6*6二维数组,i,j控制行列,x,y控制元素 */ 4 int arr[6][6]={0},count = 1,i,j,x,y; 5 /* 输入 */ 6 for(i=0,j=5;i<=5&&j>=0; ++i,--j) 7 { //左右(x不变,y变) 8 for(x=y=i; y<=j; ++y){ 9 arr[x][y] = count++; 10 } 11 //上下(x变,y不变) 12 for(x=i+1; x<=j; ++x){ 13 arr[x][y-1] = count++; 14 } 15 //右左(x不变,y变) 16 for(y=j-1; y>=i; --y){ 17 arr[x-1][y] = count++; 18 } 19 //下上(x变,y不变) 20 for(x=j-1; x>i; --x){ 21 arr[x][y+1] = count++; 22 } 23 } 24 /* 输出 */ 25 for(int m=0; m<=5; ++m){ 26 for(int n=0; n<=5; ++n){ 27 printf("%4d",arr[m][n]); 28 } 29 printf("\n"); 30 } 31 return 0; 32 }
5、整形变量的交换，位异或
1 #include <stdio.h> 2 int main() 3 { 4 int a=49,b=37; 5 a = a^b;//a包含b 6 b = a^b; //取出a赋值给b 7 a = a^b; //取出b赋值给a 8 printf("%d %d",a,b); 9 return 0; 10 }
