C编程（C语言程序设计，大连理工大学MOOC)

Posted on 2019-10-23 17:08 金色的省略号阅读(22643) 评论(0) 编辑收藏举报

仅作参考，请指正（都提交通过，但是也有错误，第22题的错误，已经修正）

1、Hello World!

1 #include <stdio.h> 
2 int main()
3 {
4     printf("Hello World!"); 
5     return 0;
6 }

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2、我爱编程

1 #include <stdio.h> 
2 int main()
3 {
4     printf("Hello C!\n"); 
5     printf("I like programming."); 
6     return 0;
7 }

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3、计算两个整数的乘积

1 #include <stdio.h> 
2 int main()
3 {
4     int a,b;
5     scanf("%d%d",&a,&b);
6     printf("%d",a*b); 
7     return 0;
8 }

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4、计算圆的面积

1 #include <stdio.h> 
2 #include <string.h>
3 #define PI 3.1415
4 int main()
5 {    
6     printf("Area=%5.2f\n", PI*4.3*4.3);
7     return 0;
8 }

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5、计算平方根

1 #include <stdio.h> 
2 #include <math.h>
3 int main()
4 {
5     double x;    
6     scanf("%lf", &x);
7     printf("%f\n", sqrt(x));
8     return 0;
9 }

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6、输出逆序数

 1 #include <stdio.h> 
 2 #include <string.h>
 3 #include <math.h>
 4 int main()
 5 {
 6     int x,y = 0;    
 7     scanf("%d", &x);
 8     while(x)
 9     {
10         y = y*10 + x%10;
11         x /= 10;
12     }
13     printf("y=%d\n", y);
14     return 0;
15 }

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7、交换两个变量

 1 #include<stdio.h>
 2 #include<math.h>
 3 
 4 int main()
 5 {
 6     int a,b,t;
 7     scanf("%d,%d",&a,&b);
 8     t = a;
 9     a = b;
10     b = t;
11     printf("%d,%d",a,b);
12     return 0;
13 }

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8、输出字符ASCII码

 1 #include<stdio.h>
 2 #include<math.h>
 3 
 4 int main()
 5 {
 6     int a;
 7     a = getchar();
 8     printf("ASCII=%d",a);
 9     return 0;
10 }

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9、求一元二次方程的两个实根

 1 #include<stdio.h>
 2 #include<math.h>
 3 
 4 int main()
 5 {
 6     float x1,x2;
 7     x1 = (-1 + sqrt(1+4*2))/2.0;
 8     x2 = (-1 - sqrt(1+4*2))/2.0;
 9     printf("x1=%.4f\n",x1);
10     printf("x2=%.4f\n",x2);
11     return 0;
12 }

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10、计算银行存款本息

 1 #include<stdio.h>
 2 #include<math.h>
 3 
 4 int main()
 5 {
 6     int money,year;
 7     double rate,sum = 0;
 8     scanf("%d%d%lf",&money,&year,&rate);
 9     sum = money*pow((1+rate),year);
10     
11     printf("sum=%7.2f",sum);
12     return 0;
13 }

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11、大小写字母转换

 1 #include <stdio.h>
 2 #include <stdio.h>
 3 #include <stdlib.h>
 4  
 5 int main()
 6 {
 7     char ch;
 8     ch = getchar();
 9     if(ch>='a'&&ch<='z')
10         ch -= 32;
11     else
12         ch += 32;
13     putchar(ch);
14     return 0;
15 }

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12、计算分段函数

 1 #include <stdio.h> 
 2 int main(void)
 3 {
 4     double x, y; 
 5     scanf("%lf",&x);
 6     if ( x<0 )
 7         y=0;
 8     else if( x<=15 )
 9         y=4*x/3;
10     else
11         y=2.5*x-10.5;
12     printf("y=%.2f",y);   
13     return 0;
14 }

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13、百分制成绩转换为五级分制成绩

 1 #include <stdio.h>
 2 #include <stdio.h>
 3 #include <stdlib.h>
 4  
 5 int main()
 6 {
 7     float achievment;
 8     scanf("%f",&achievment);
 9     
10     int a = achievment;
11     char ch;
12     
13     switch(a/10){
14         case 10:
15         case 9:ch = 'A';break;
16         case 8:ch = 'B';break;
17         case 7:ch = 'C';break;
18         case 6:ch = 'D';break;
19         default:ch = 'E';
20     }
21     printf("grade:%c\n",ch);
22     
23     return 0;
24 }

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14、输出水仙花数

 1 #include <stdio.h>
 2 #include <stdio.h>
 3 #include <stdlib.h>
 4  
 5 int main()
 6 {
 7     int i;
 8     scanf("%d",&i);
 9     
10     int a = i%10, b = i/10%10, c = i/100;
11     if(a*a*a + b*b*b + c*c*c == i)
12         printf("%d是水仙花数！",i);
13     else
14         printf("%d不是水仙花数！",i);
15     
16     return 0;
17 }

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15、用for语句实现判断并求和

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5     int sum = 0;
 6     for(int i=1; i<=100;  ++i)
 7     {
 8         if(i%3==0 && i%5==1)
 9             sum += i;
10     }
11     printf("sum=%d",sum);
12     
13     return 0;
14 }

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16、用do while 语句实现从键盘输入一组整数，求平均值

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5     int i=0, x;
 6     float sum = 0;
 7     do{
 8         scanf("%d",&x);
 9         if(x<0) break;
10         sum += x;
11         i++;
12     }while(x>=0);
13     printf("AVE=%.2f\n",sum/i);    
14     return 0;
15 }

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17、用while语句实现计算圆周率 pi (3.14) 的近似值

 1 #include<stdio.h>
 2 #include <math.h>
 3 #define EPS  1e-5
 4 int main()
 5 {
 6     float pi = 0, sign = 1, x = 1;
 7     
 8     while(fabs(sign/x) > EPS)
 9     {
10         pi += sign/x;
11         x += 2;
12         sign = -sign;    
13     }
14     printf("pi=%.2f\n",pi*4);    
15     return 0;
16 }

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18、求两个整数的最大公约数

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int GCD(int x, int y);
 5 int main()
 6 {
 7     int a,b;
 8     scanf("%d%d",&a,&b);
 9     printf("GCD=%d\n",GCD(a,b));
10     return 0;
11 }
12 
13 int GCD(int x, int y){
14     return y == 0 ? x : GCD(y, x%y); 
15 }

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19、找素数

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int isPrime(int x);
 5 int main()
 6 {
 7     int a;
 8     scanf("%d",&a);
 9     for(int i=a+1;;++i){
10         if(isPrime(i)){
11             printf("prime=%d\n",i);
12             break;
13         }            
14     }   
15     return 0;
16 }
17 
18 int isPrime(int x){
19     for(int i=2; i<x; ++i)
20         if(x%i==0)
21             return 0;
22     return 1;
23 }

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20、斐波那契数列求和

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     int sum = 0, a=1,b=1;
 7     for(int i=0;i<20;i+=2){
 8         sum += a+b;
 9         a = a+b;
10         b = a+b;
11     } 
12     printf("sum=%d\n",sum);
13     return 0;
14 }

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21、逆序存放数据

 1 #include<stdio.h>
 2 #define N 100
 3 int main()
 4 {
 5     int arr[N] = {0}, n=6;
 6     for(int i=n-1; i>=0; --i)
 7         scanf("%d",&arr[i]);
 8     for(int j=0; j<n; ++j)
 9         printf("%d\n",arr[j]);
10     return 0;
11 }

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22、找出一维整型数组中的次最大值

#include<stdio.h>
#define N 5
/*设次大值一定存在*/
int main()
{
    int i, j, arr[N+1] = {0};
    /* 输入5个数 */
    for(i=0; i<N; ++i)
        scanf("%d",&arr[i]);
    /* 冒泡排序 */
    for(i=0; i<N-1; ++i)
        for(j=0; j<N-i-1; ++j)
            if(arr[j]<arr[j+1]){
                int t = arr[j];
                arr[j] = arr[j+1];
                arr[j+1] = t;
            }
    /* 求次最大值下标i*/
        for(i=1; arr[0]==arr[i] && i<N; ++i)
            ;
        /*if(i==N)
            printf("次大值不存在!\n");*/
    printf("次最大值=%d",arr[i]);
    return 0;
}

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/*
    求最大值、次大值可以不用排序
 */
#include <stdio.h>
#define N 5
int main()
{
    int i, arr[N] = {0};
    int max1, max2;
    
    scanf("%d%d",&arr[0],&arr[1]);
    max1 = max2 = arr[0];
    arr[1] > max1 ? (max1 = arr[1]) : (max2  = arr[1]);
    
    for(i=2; i<N; ++i){
        scanf("%d",&arr[i]);
        if(arr[i]>max1){
            max2 = max1;
            max1 = arr[i];
        }
        else if(arr[i]>max2){
            max2 = arr[i];
        }
    }

        /*if(max1==max2)
            printf("次大值不存在!\n");
        else
            printf("次最大值=%d",max2);*/

    /*次最大值 max2 是存在的 */
    printf("次最大值=%d",max2);
    return 0;
}

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#include <stdio.h>
#include <limits.h>
#define N 5
int main()
{
    int i, arr[N] = {0};
    int max1, max2;
    
    max1 = max2 = INT_MIN;
    
    for(i=0; i<N; ++i){
        scanf("%d",&arr[i]);
        if(arr[i]>max1){
            max2 = max1;
            max1 = arr[i];
        }
        else if(arr[i]>max2){
            max2 = arr[i];
        }
    }    
    /* 次最大值 max2 */
    if(max1  == INT_MIN)
        printf("次大值不存在!\n");
    else
        printf("次最大值=%d",max2);
    return 0;
}

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23、调整最大值的位置

 1 #include<stdio.h>
 2 #define N 100
 3 int main()
 4 {
 5     int arr[N] = {0}, n=6, max=0, maxi=0;
 6     scanf("%d",&arr[0]);
 7     max=arr[0];
 8     
 9     for(int i=1; i<n; ++i){
10         scanf("%d",&arr[i]);
11         if(arr[i]>max){
12             max = arr[i];
13             maxi = i;
14         }
15             
16     }
17     int t = arr[n-1];
18     arr[n-1] = arr[maxi];
19     arr[maxi] = t;
20     
21     for(int j=0; j<n; ++j)
22         printf("%d\n",arr[j]);
23     return 0;
24 }

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24、连接两个字符串

 1 #include<stdio.h>
 2 #include<string.h>
 3 #define N 100
 4 int main()
 5 {
 6     char a[2*N] = "", b[N] = "";
 7     scanf("%s%s",a,b);
 8     /* strcpy(&a[strlen(a)],b);//没有用strcat用的strcpy
 9     */
10     //不用函数
11     int i;
12     for(i=0; a[i]; ++i);//求字符串'\0'下标
13     char *p = a+i, *q = b;
14     while(*q)
15     {
16         *p++ = *q++;
17     }
18     *p = '\0'; 
19     
20     printf("%s\n",a);
21     return 0;
22 }

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 1 #include<stdio.h>
 2 #include<string.h>
 3 #define N 100
 4 int main()
 5 {
 6     char a[2*N] = "", b[N] = "";
 7     scanf("%s%s",a,b);
 8    
 9     char *p = a, *q = b;
10     while(*p) p++;
11     while((*p++=*q++)!='\0');
12    
13     printf("%s\n",a);
14     return 0;
15 }

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25、求矩阵外围元素之和

 1 #include <stdio.h>
 2 #include <malloc.h>
 3 int main()
 4 {
 5     int sum=0, n=3;    
 6     int *arr = (int*)malloc(sizeof(int)*n*n); //一维模拟二维数组
 7     
 8     for(int i=0; i<n*n; ++i)
 9     {
10         scanf("%d",&arr[i]);
11     } 
12     
13     for(int i=0; i<n; ++i)
14     {
15         for(int j=0; j<n; ++j)
16         {
17             if(i==0||i==n-1 || j==0|| j==n-1 )
18             {
19                 sum += arr[i*n+j]; //一行n个
20             }         
21         }      
22     }
23     
24     printf("%d",sum);
25     
26     return 0;
27 }

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26、求矩阵主对角线和副对角线元素之和

 1 #include <stdio.h>
 2 #define N 5
 3 int main()
 4 { 
 5     char str[N][N];
 6         int i,j,sum=0;
 7 
 8         for(i=0; i<N; ++i)
 9             for(j=0; j<N; ++j)
10                 scanf("%d",&str[i][j]);
11 
12         for(i=0; i<N; ++i)
13             for(j=0; j<N; ++j)
14             {
15                 if(i==j)
16                     sum += str[i][j];
17                 if(i==N-j-1)
18                     sum += str[i][j];
19             }
20         printf("sum=%d\n",sum);
21     return 0;
22 }

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27、将字符串的小写字母转换为大写字母

 1 #include <stdio.h>
 2 #define N 1000
 3 int main()
 4 {
 5     char str[N]="";
 6     int i=0;
 7     gets(str);
 8 
 9     while(str[i]){
10         if(str[i]>='a'&&str[i]<='z')
11             str[i] -= 32;
12         i++;
13     }
14     printf("%s\n",str);
15     return 0;
16 }

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28、编写函数，计算银行存款本息并输出

 1 #include <stdio.h> 
 2 #include <stdlib.h>
 3 double fun(int money,int year, double rate)
 4 {
 5     double sum = money;
 6     while(year--){
 7         sum = sum*(1+rate);
 8     }
 9     return sum;
10 }
11 int main()
12 {
13     int money, year;
14     double rate, sum=0;
15     scanf("%d%d%lf",&money,&year,&rate);
16     sum = fun(money,year,rate);
17     printf("sum=%.2f",sum);
18     return 0;
19 }

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29、数值转换

 1 /*位运算*/
 2 #include <stdio.h>
 3 void fun(int x)
 4 {
 5     int j=31;/*按32位定义*/   
 6     while(!((x&(1<<j))>>j))/*去前面的0*/
 7         j--;
 8     for(; j>=0; j--)/*按位输出*/
 9         printf("%d", (x&(1<<j))>>j);
10 }
11 int main()
12 {
13     int x;
14     scanf("%d",&x);
15     fun(x);
16     return 0;
17 }

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30、求一组数中大于平均值的数的个数

 1 #include <stdio.h>
 2 #define N 100
 3 
 4 int main()
 5 {    
 6     int num[N] = {0},count=0;
 7     double sum = 0;
 8     for(int i=0; i<10; ++i){
 9         scanf("%d",&num[i]);
10         sum += num[i];
11     }
12     for(int j=0; j<10; ++j)
13         if(num[j]>sum/10)
14             count++;
15     printf("%d",count);
16     return 0;
17 }

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31、求x的n次方

 1 #include <stdio.h>
 2 double cube(double x,int n)
 3 {
 4     if(n ==1)
 5         return x;
 6     else
 7         return x*cube(x,n-1);
 8 }
 9 int main()
10 {
11     double x,y;
12     int n;
13     scanf("%lf%d",&x,&n);
14     y=cube(x,n);
15     printf("%f",y);
16     return 0;
17 }

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32、输出最大、最小数

 1 #include <stdio.h>
 2 void fun(int *arr,int *max,int *min){
 3     *max = *min = arr[0];
 4     for(int i=1; i<10; ++i){
 5         if(arr[i]>*max)
 6             *max = arr[i];
 7         if(arr[i]<*min)
 8             *min = arr[i];
 9     }
10 }
11 int main()
12 {
13     int max,min;
14     int arr[10] = {0};
15     for(int i=0; i<10; ++i){
16         scanf("%d",&arr[i]);
17     }    
18     fun(arr,&max,&min);
19     printf("max=%d,min=%d",max,min);
20     return 0;
21 }

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33、任意整数转换为千分位分隔的字符形式

 1 #include <stdio.h>
 2 #define N 100
 3 int main()
 4 {
 5     int n;
 6     scanf("%d",&n);
 7     int arr[N] = {0},index = 0;
 8     while(n)
 9     {
10         arr[index++] = n%10;
11         n /= 10;
12     }
13     for(int i=index-1; i>=0; --i)        
14     {
15         printf("%d",arr[i]);
16         if(i%3==0&&i)
17             printf(",");
18     }
19     return 0;
20 }

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34、利用指针编写程序，统计字符串的长度

 1 #include <stdio.h>
 2 #define N 100
 3 int main()
 4 {    
 5     char str[N] = "";
 6     gets(str);
 7     char *p = str;
 8     int len = 0;
 9     while(*p)
10     {
11         len++;
12         p++;
13     }
14     printf("Length of the string is %d\n",len);
15     return 0;
16 }

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35、利用指针编程，将数组中所有元素的值对称交换

 1 #include <stdio.h>
 2 #define N 10
 3 int main()
 4 {    
 5     int arr[N] = {0};
 6     for(int i=0; i<N; ++i)
 7         scanf("%d",&arr[i]);
 8     int *p = arr, *q = arr+N-1;
 9     while(p<q)
10     {
11         int t = *p;
12         *p = *q;
13         *q = t;
14         p++, q--;
15     }
16     for(int j=0; j<N; ++j)
17         printf("%2d",arr[j]);
18     return 0;
19 }

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36、利用指针编写程序，求一维数组中的最大和最小的元素值

 1 #include <stdio.h>
 2 #define N 10
 3 int main()
 4 {    
 5     int arr[N] = {0};
 6     for(int i=0; i<N; ++i)
 7         scanf("%d",&arr[i]);
 8     int max, min;
 9     max = min = arr[0];
10     for(int j=1; j<N; ++j)
11     {
12         if(arr[j]>max)
13             max = arr[j];
14         if(arr[j]<min)
15             min = arr[j];
16     }
17     printf("max=%d,min=%d",max,min);
18     return 0;
19 }

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37、利用指针编写一函数，输入3个整数，按由大到小的顺序将它们输出

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <string.h>
 4 #define N 256
 5 
 6 void swap(int *a, int *b)
 7 {
 8     int t = *a;
 9     *a = *b;
10     *b = t;
11 }
12 int main( )
13 {    
14     int arr[N] = {0};
15     for(int i=0; i<3; ++i)
16         scanf("%d",&arr[i]);
17     if(arr[0]<arr[1])
18         swap(&arr[0],&arr[1]);
19     if(arr[0]<arr[2])
20         swap(&arr[0],&arr[2]);
21     if(arr[1]<arr[2])
22         swap(&arr[1],&arr[2]);
23     for(int j=0;j<3; ++j)
24         printf("%3d",arr[j]);
25     return 0;
26 }

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38、用指向数组的指针变量实现输出指定学生的全部成绩

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <string.h>
 4 #define N 256
 5 
 6 int main( )
 7 {    
 8     float score[][4]={{60,70,80,90},{56,89,67,88},{34,78,90,66}};
 9     float (*p)[4] = score;
10     int n;
11     scanf("%d",&n);
12     for(int i=0;i<4;++i)
13         printf("%8.2f",p[n][i]);
14     return 0;
15 }

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39、某班有5名同学，建立一个学生的简单信息表，包括学号、姓名、3门课程的成绩，编写程序，计算每名学生的平均成绩及名次

 1 /* 
 2 测试数据
 3 201701 zhao 29.8 85.4 65.4
 4 201702 qian 96.5 87.5 65.4
 5 201703 sun 85.4 65.4 84.6
 6 201704 li 63.4 95.4 86.3
 7 201705 zhou 65.9 84.6 97.5 
 8 */
 9 #include<stdio.h>
10 
11 struct student{
12     long no;
13     char name[20];
14     float score[3];
15 }stu[5],*p;
16 
17 int rank(float *ave, float score){
18     int rank = 5;
19     for(int i=0; i<5; ++i)
20         if(ave[i]<score)
21             rank--;
22     return rank;
23 }
24 
25 int main()
26 { 
27     float ave[5] = {0.0};
28     int index = 0;
29     for(p=stu; p<stu+5; ++p){ //stu+5
30         scanf("%ld %s %f %f %f",
31             &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]);
32         ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0;
33     }
34     
35     printf("Number:  Name:        score:       Average：  rank:\n");
36     for(index=0,p=stu; p<stu+5; ++p){
37         printf("%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n",
38             p->no,p->name,p->score[0],p->score[1],
39             p->score[2],ave[index++],rank(ave,ave[index]));
40     }
41     return 0;
42  }

View Code

40、某班有10名同学，建立学生结构体类型，包括学号、姓名、3门课程的成绩，编写程序，读入已准备好的文本文件student1.txt，为结构体数组变量赋值，计算每名学生的平均成绩及名次。结果输出到屏幕的同时保存到student2.txt文件中

 1 #include <stdio.h>
 2  
 3 /* 结构体定义 */
 4 struct student{
 5     long no;
 6     char name[20];
 7     float score[3];
 8 }stu[10],*p;
 9  
10 /* 计算名次 */
11 int rank(float *ave, float score, int n){
12     int rank = n;
13     for(int i=0; i<n; ++i)
14         if(ave[i]<score)
15             rank--;
16     return rank;
17 }
18  
19 int main()
20 {
21     /* 打开文件 */   
22     FILE *fp1,*fp2;
23     fp1 = fopen("student1.txt","r");
24     fp2 = fopen("student2.txt","w");
25      
26     /* 读取数据 计算平均值 */
27     float ave[10] = {0.0};
28     int index = 0; 
29     for(p=stu; p<stu+10; ++p){ //stu+10
30         fscanf(fp1,"%ld %s %f %f %f",
31             &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]);
32         ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0;
33     }
34     /* 写入文件 */
35     for(index = 0,p=stu; p<stu+10; ++p){
36         fprintf(fp2,"%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n",
37             p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index],10));
38     }   
39     /* 关闭文件 */
40     fclose(fp1);
41     fclose(fp2);
42     return 0;
43 }

View Code

 1 测试数据 student1.txt
 2 201701 zhao 29.8 85.4 65.4
 3 201702 qian 96.5 87.5 65.4
 4 201703 sun 85.4 65.4 84.6
 5 201704 li 63.4 95.4 86.3
 6 201705 zhou 65.9 84.6 97.5
 7 201706 wu 39.8 85.4 75.4
 8 201707 zheng 96.5 82.5 75.9
 9 201708 wang 75.4 85.4 94.6
10 201709 feng 73.4 95.4 56.3
11 2017010 chen 75.9 74.6 77.5

测试数据

 1 /* 
 2 测试数据 student1.txt
 3 201701 zhao 29.8 85.4 65.4
 4 201702 qian 96.5 87.5 65.4
 5 201703 sun 85.4 65.4 84.6
 6 201704 li 63.4 95.4 86.3
 7 201705 zhou 65.9 84.6 97.5
 8 201706 wu 39.8 85.4 75.4
 9 201707 zheng 96.5 82.5 75.9
10 201708 wang 75.4 85.4 94.6
11 201709 feng 73.4 95.4 56.3
12 2017010 chen 75.9 74.6 77.5
13  */
14 #include <stdio.h>
15 struct student{
16     long no;
17     char name[20];
18     float score[3];
19 }stu[10],*p;
20 
21 int rank(float *ave, float score){
22     int rank = 10;
23     for(int i=0; i<10; ++i)
24         if(ave[i]<score)
25             rank--;
26     return rank;
27 }
28 
29 int main()
30 { 
31     FILE *fp;
32     fp = fopen("d:\\student1.txt","r");
33     float ave[10] = {0.0};
34     int index = 0;
35     for(p=stu; p<stu+10; ++p){ //stu+10
36         fscanf(fp,"%ld %s %f %f %f",
37             &p->no,p->name,&p->score[0],&p->score[1],&p->score[2]);
38         ave[index++] = (p->score[0]+p->score[1]+p->score[2])/3.0;
39     }
40     printf("Number:  Name:        score:       Average：  rank:\n");
41     for(index = 0, p=stu; p<stu+10; ++p){
42         printf("%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n",
43             p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index]));
44     }
45     fclose(fp);
46     /* ---------------------------------------------- */
47     fp = fopen("d:\\student2.txt","w");
48     for(index = 0, p=stu; p<stu+10; ++p){
49         fprintf(fp,"%-9ld%-10s%-5.1f%-5.1f%-8.1f%-10.1f%-d\n",
50             p->no,p->name,p->score[0],p->score[1],p->score[2],ave[index++],rank(ave,ave[index]));
51     }
52     fclose(fp);
53     return 0;
54  }

View Code

41、输入并保存5名职工的信息，计算并输出平均工资，再按照工资从高到低的顺序输出

 1 #include <stdio.h> 
 2 #include <stdlib.h>
 3 typedef struct employee EMPLOYEE;
 4 struct employee{
 5     int no;
 6     char name[10];
 7     double salary;
 8 };
 9 int compare(const void * a,const void *b)/*比较函数*/
10 {
11     return (*(EMPLOYEE*)a).salary < (*(EMPLOYEE*)b).salary;
12 }
13 
14 int main()
15 {
16     double sum = 0;
17     EMPLOYEE e[5];
18     for(int i=0; i<5; ++i){
19         scanf("%d%s%lf",&e[i].no,e[i].name,&e[i].salary);
20         sum += e[i].salary;
21     }
22     qsort(e,5,sizeof(EMPLOYEE),compare);
23     printf("The Average=%-6.1f\n",sum/5);
24     for(int i=0; i<5; ++i){
25         printf("%-10d%-10s%-6.1f\n",e[i].no,e[i].name,e[i].salary);
26     }        
27     return 0;
28 }

View Code

 1 #include <stdio.h> 
 2 typedef struct employee EMPLOYEE;
 3 struct employee{
 4     int no;
 5     char name[10];
 6     double salary;
 7 };
 8 /* 选择排序 */
 9 void sortSalary(EMPLOYEE e[]){
10     for(int i=0; i<5-1; ++i)
11         for(int j=i+1; j<5; ++j)
12             if(e[i].salary<e[j].salary)
13             {
14                 EMPLOYEE t = e[i];
15                 e[i] = e[j];
16                 e[j] = t;
17             }
18 }
19 
20 int main()
21 {
22     double sum = 0;
23     EMPLOYEE e[5];
24     for(int i=0; i<5; ++i){
25         scanf("%d%s%lf",&e[i].no,e[i].name,&e[i].salary);
26         sum += e[i].salary;
27     }
28     sortSalary(e);
29     printf("The Average=%-6.1f\n",sum/5);
30     for(int i=0; i<5; ++i){
31         printf("%-10d%-10s%-6.1f\n",e[i].no,e[i].name,e[i].salary);
32     }        
33     return 0;
34 }

View Code

1 测试数据
2 19610901 zhao 8524
3 20170205 qian 6605
4 20100320 sun 6750
5 19730205 wang 8230
6 19800725 zhou 7590

测试数据

42、编写程序键盘输入整型变量n，从低位开始取出整型变量n偶数位上的数依次放在整型变量s中，然后输出s

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5     int n;
 6     scanf("%d",&n);
 7     int s=0,i=1;
 8     while(n)
 9     {
10         n/=10;
11         s += n%10*i;
12         i *= 10;
13         n/=10;
14     }
15     printf("%d",s);
16     return 0;
17 }

View Code

 1 #include <stdio.h> 
 2 #define N 100
 3 int main()
 4 {
 5     int n,s=0,i=1;//n的偶数位依次放在s中
 6     scanf("%d",&n);
 7     while(n>10)//确保不取奇数位
 8     {
 9         s += i*(n/10%10); //取偶数位累加    
10         n /= 100;         //去两位
11         i *= 10;          //升位
12     }  
13     printf("%d\n",s);
14     return 0;
15 }

View Code

 1 #include <stdio.h> 
 2 #define N 100
 3 int main()
 4 {
 5     int s;
 6     scanf("%d",&s);
 7   
 8     int arr[N] = {0};
 9     int i=0;
10     while(s>10)
11     {
12         arr[i++] = s/10%10;    
13         s /= 100;
14     }
15     for(int j=i-1; j>=0; --j)
16         printf("%d",arr[j]);
17     return 0;
18 }

View Code

其他课程相关

1、字符串a下标值为偶数的元素由小到大排序，其他元素不变

 1 #include<stdio.h>
 2 int main()
 3 {
 4     char a[]="labchmfye",t;
 5     int len = 9;
 6     
 7     int i,j;
 8     for(i=0;i<len-2;i+=2)
 9     {
10         for(j=i+2;j<len; j+=2){
11             if(a[i]>a[j])
12             {
13                 t=a[i];
14                 a[i]=a[j];
15                 a[j]=t;
16             }
17         }        
18     }        
19     puts(a);
20     printf("\n");
21     return 0;
22 }

2、十进制正整数转换为二进制1

 1 /*位运算*/
 2 #include <stdio.h>
 3 void fun(int x)
 4 {
 5     int j=31;/*按32位定义*/   
 6     while(!((x&(1<<j))>>j))/*去前面的0*/
 7         j--;
 8     for(; j>=0; j--)/*按位输出*/
 9         printf("%d", (x&(1<<j))>>j);
10 }
11 int main()
12 {
13     int x;
14     scanf("%d",&x);
15     fun(x);
16     return 0;
17 }

3、十进制正整数转换为二进制2

 1 #include <stdio.h>
 2 #define N 100
 3 void fun(int n, int base)
 4 {
 5     int num[N] = {0}, i=0;
 6     while(n)
 7     {
 8         num[i++] = n%base;        
 9         n /= base;
10     }
11     for(int j=i-1;j>=0; --j)
12         printf("%d",num[j]);
13 }
14 int main()
15 {    
16     int n;
17     scanf("%d",&n);
18     fun(n,2);
19     return 0;
20 }

4、螺旋二维数组

 1 #include<stdio.h>
 2 int main()
 3 {   /* 6*6二维数组,i,j控制行列,x,y控制元素 */
 4     int arr[6][6]={0},count = 1,i,j,x,y;
 5     /* 输入 */
 6     for(i=0,j=5;i<=5&&j>=0; ++i,--j)
 7     {   //左右(x不变,y变)
 8         for(x=y=i; y<=j; ++y){
 9             arr[x][y] = count++;
10         }
11         //上下(x变,y不变)
12         for(x=i+1; x<=j; ++x){
13             arr[x][y-1] = count++;
14         }
15         //右左(x不变,y变)
16         for(y=j-1; y>=i; --y){
17             arr[x-1][y] = count++;
18         }
19         //下上(x变,y不变)
20         for(x=j-1; x>i; --x){
21             arr[x][y+1] = count++;
22         }
23     }
24     /* 输出 */
25     for(int m=0; m<=5; ++m){
26         for(int n=0; n<=5; ++n){
27             printf("%4d",arr[m][n]);
28         }
29         printf("\n");
30     }
31     return 0;
32  }

5、整形变量的交换，位异或

 1 #include <stdio.h>
 2 int main()
 3 {
 4     int a=49,b=37;
 5     a = a^b;//a包含b
 6     b = a^b; //取出a赋值给b
 7     a = a^b; //取出b赋值给a
 8     printf("%d %d",a,b);
 9     return 0;
10 }

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C编程（C语言程序设计，大连理工大学MOOC)