摘要:
## 特殊角三角函数值 $\sin{\dfrac{\pi}{12}}=\dfrac{\sqrt{6}-\sqrt{2}}{4} \space\space\space\space\space\space\space\space \cos{\dfrac{\pi}{12}}=\dfrac{\sqrt{6}+\sqrt{2}}{4} \space\space\space\space\space\space\space\space \tan{\dfrac{\pi}{12}}=2-\sqrt{3}$ 阅读全文
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