PTA 乙级 1056 组合数的和 (15分) C/C++

 

 

#include<iostream>

using namespace std;

int main() {
    int n = 0;
    int num[10] = { 0 };
    int sum = 0;
    cin >> n;
    for (int i = 0; i < n; ++i)cin >> num[i];
    for (int i = 0; i < n; i++) {
        for (int j = i + 1; j < n; ++j) {
            if (num[i] != 0) sum += num[i] * 10 + num[j]; //保证十位不为零
            if (num[j] != 0) sum += num[j] * 10 + num[i];
        }
    }
    cout << sum;
    return 0;
}

 

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