PTA 乙级 1001 害死人不偿命的(3n+1)猜想 (15分) C/C++

 

 C

#include<stdio.h>

int main(){
    int n = 0;
    int num = 0;
    //printf("请输入一个不超过1000的正整数：");
    scanf("%d", &num);
    while(num != 1){
        if(num%2 == 0){
            num = num / 2;
            n++;
        }else{
            num = (3*num + 1) / 2;
        //    printf("%d\n",num)]; 
            n++;
        }
    }
    printf("%d\n", n);
    return 0;
    
}