C++ Primer第5版 第九章课后练习答案

合集《C++ Primer第5版》 课后练习答案 - 丸子球球 - 博客园 (cnblogs.com)

练习9.1

(a)list更合适，因为按照字典序插入到容器中代表需要在容器中间插入元素
(b)deque更合适，因为deque支持双端插入和删除
(c)无具体的插入删除操作，读取整数数量也是未知，可以选择vector

练习9.2

int main(int argc, char* argv[])
{
    std::list<std::deque<int>> lq;
}

练习9.3

指向同一个容器的元素，或者尾后迭代器
end不在begin之前

练习9.4

bool find(vector<int>::const_iterator& begin, vector<int>::const_iterator& end, int i) {
    while (begin != end) {
        if (*begin == i)return true;
    }
    return false;
}

练习9.5

vector<int>::const_iterator& find(vector<int>::const_iterator& begin, vector<int>::const_iterator& end, int i) {
    while (begin != end) {
        if (*begin == i)return begin;
    }
    std::cerr << "don't find the num in the arrange";
    return end;
}

练习9.6

在C++定义的容器类型中，只有vector和queue容器提供迭代器算数运算和除!=和==之外的关系运算

练习9.7

vector::size_type

练习9.8

读取
list::iterator||list::const_iterator
写入
list::iterator

练习9.9

cbegin返回的是const迭代器对象，begin不是

练习9.10

it1:vector::iterator
it2:constvector::iteratorit3:vector::const_iterator
it4:const vector::const_iterator

练习9.11

vector<int> v1;//空
vector<int> v2(v1);//v1的拷贝
vector<int> v3{ 0,1,2,3 };//初始化为初始化列表的拷贝
vector<int> v4(v3.begin(), v3.end());//初始化为迭代器之间元素的拷贝
vector<int> v5(10);//包含10个元素，每一个都被值初始化为0
vector<

练习9.12

接受一个容器创建其拷贝的构造函数：要求具有相同的容器类型，保存的是相同的元素类型
接受两个迭代器创建拷贝的构造函数：只要求迭代器范围内的元素类型相同

练习9.13

int main(int argc, char* argv[])
{
    list<int> li{ 0,1,2,3 };
    vector<double> vd(li.begin(), li.end());
    for (auto i : vd)
        cout << i << " ";
    cout << endl;
    vector<int> vi{ 0,1,2,3 };
    vector<double> vd2(vi.begin(), vi.end());
    for (auto i : vd2)
        cout << i << " ";
}

练习9.14

int main(int argc, char* argv[])
{
    list<const char*> lc;
    vector<string> vs;
    vs.assign(lc.begin(), lc.end());
}

练习9.15

template<typename T>
bool check(const vector<T>& v1, const vector<T>& v2) {
    return v1 == v2;
}

int main(int argc, char* argv[])
{
    vector<string> vs1{ "012" };
    vector<string> vs2{ "012","123" };
    cout << (check(vs1, vs2) ? "相等" : "不相等");
}

练习9.16

template<typename T>
bool check(const list<T>& v1, const vector<T>& v2) {
    if (v1.size() == v2.size()) {
        auto j = v2.begin();
        for (auto i = v1.begin(); i !=v1.end() ; i++,j++) {
            if (*i != *j)return false;
        }
        return true;
    }
    return false;
}

int main(int argc, char* argv[])
{
    list<string> vs1{ "012" };
    vector<string> vs2{ "012","123" };
    cout << (check(vs1, vs2) ? "相等" : "不相等");
}

练习9.17

要求不是无序关联容器，c1和c2必须是相同类型的容器，且必须保存相同类型的元素

练习9.18

int main(int argc, char* argv[])
{
    std::deque<string> ds;
    string s;
    while (cin >> s) {
        ds.emplace_back(s);
        s.clear();
    }
    for (auto it = ds.begin(); it != ds.end(); it++) {
        cout << *it << endl;
    }
}

练习9.19

int main(int argc, char* argv[])
{
    list<string> ls;
    string s;
    while (cin >> s) {
        ls.emplace_back(s);
        s.clear();
    }
    for (auto it = ls.begin(); it != ls.end(); it++) {
        cout << *it << endl;
    }
}

练习9.20

int main(int argc, char* argv[])
{
    list<int> li;
    int i;
    deque<int> di1, di2;
    while (cin >> i) {
        li.emplace_back(i);
    }
    for (auto it = li.begin(); it != li.end(); it++) {
        if ((*it) % 2)di1.emplace_back(*it);
        else di2.emplace_back(*it);
    }
}

练习9.21

int main(int argc, char* argv[])
{
    vector<string> vst;
    string word;

    auto iter = vst.begin();
    while (cin >> word) {
        iter = vst.insert(iter, word);
    }
}

将iter初始化为vst.begin()，第一次调用insert会将我们刚刚读入的string插入到iter所指向的元素之前的位置。

练习9.22

int main(int argc, char* argv[])
{
    vector<int> iv{ 0,1,2,3,4,5 };
    vector<int>::iterator iter = iv.begin(), mid = iv.begin() + iv.size() / 2;
    int some_val = 0;
    while (iter!=mid)
    {
        if (*iter == some_val)
            iv.insert(iter, 2 * some_val);
    }
}

该程序会在满足程序的情况下在vector开头插入元素，导致迭代器失效，应更新循环中的迭代器，并保证迭代器不会陷入无限循环

int main(int argc, char* argv[])
{
    vector<int> iv{ 0,1,2,3,4,5 };
    vector<int>::iterator iter = iv.begin(), mid = iv.begin() + iv.size() / 2;
    int some_val = 0;
    while (iter!=mid)
    {
        if (*iter == some_val) {
            iter = iv.insert(iter, 2 * some_val);
            iter += 2;
        }        
        else
            iter++;
        mid = iv.begin() + iv.size() / 2;
    }
}

练习9.23

val，val2，val3和val4的值都相同

练习9.24

at：有未经处理的异常: Microsoft C++ 异常: std::out_of_range
下标运算符：vector subscript out of range
front：front() called on empty vector
begin：cant't dereference value-initialized vector iterator

练习9.25

elem1与elem2相等不会删除容器元素，如果elem2时尾后迭代器会删除所有elem1到elem2的所有元素（不包括elem2），如果elem1和elem2皆为尾后迭代器则不会删除元素

练习9.26

int main(int argc, char* argv[])
{
    int ia[] = { 0 ,1,1,2,3,5,8,13,21,55,89 };
    vector<int> iv;
    iv.assign(ia, ia + sizeof(ia) / sizeof(int));
    auto it = iv.begin();
    while (it!=iv.end())
    {
        if (!(*it % 2))
            it = iv.erase(it);
        else it++;
    }


    list<int> il;
    il.assign(ia, ia + sizeof(ia) / sizeof(int));
    auto it2 = il.begin();
    while (it2 != il.end())
    {
        if (*it2 % 2)
            it2 = il.erase(it2);
        else it2++;
    } 
}

练习9.27

int main(int argc, char* argv[])
{
    forward_list<int> flst = { 0,1,2,3,4,5,6,7,8,9 };
    auto prev = flst.before_begin(), curr = flst.begin();
    while (curr != flst.end()) {
        if (*curr % 2) {
            curr = flst.erase_after(prev);
        }
        else {
            prev = curr;
            curr++;
        }        
    }
}

练习9.28

void fl_find_insert(forward_list<string>& flst, string& s1, string& s2) {
    auto prev = flst.before_begin(), curr = flst.begin();
    while (curr != flst.end()) {
        if (*curr == s1) {
            flst.insert_after(prev, s2);
            return;
        }
        else {
            prev = curr;
            ++curr;
        }
    }
    flst.insert_after(prev, s2);
}

练习9.29

vec.resize(100)：调整vec大小为100，由于vec原来包含25个元素，将75个值为0的元素添加到vec末尾
vec.resize(10)：调整vec大小为10，由于vec原来包含25个元素，将vec末尾15个元素删除

练习9.30

元素必须能进行值初始化，若为类类型元素则必须提供默认值或者默认构造函数

练习9.31

list迭代器没有递增递减的操作，需要修改为advance(iter, 2);
forward_list没有insert和erase操作需要修改

练习9.32

不合法，++递增符改变了iter的值，将产生未定义的行为。因为赋值运算符左右两端的运算对象都用到了iter，并且右侧的运算对象还改变了iter的值

练习9.33

迭代器失效

练习9.34

遍历容器，查找所有为奇数的元素并复制该元素插入到容器中，但因为只递增了一次导致程序只会卡在第一次找到奇数的时候

练习9.35

容器的size是指它已经保存的元素的数目
容器的capacity是在不分配新的内存空间的前提下他最多能保存多少元素

练习9.36

不可能，因为size必然小于等于capacity

练习9.37

list没有capacity是因为不要求空间是连续的
array没有capacity是因为array不允许修改空间大小

练习9.38

int main(int argc, char* argv[])
{
    vector<int> vec1;
    int a;
    while (cin >> a)
    {
        vec1.push_back(a);
        cout << "vector的大小" << vec1.size() << endl;;
        cout << "vector的容量" << vec1.capacity() << endl;
    }

}

练习9.39

为vector分配1024个string元素的内存，传入值，然后插入容器一半数量的空string元素

练习9.40

256:1024
512:1024
1000:1536
1024:2304

练习9.41

int main(int argc, char* argv[])
{
    vector<char>cvec(10, 'c');
    char *charray=new char[cvec.size()];
    memcpy(charray, &cvec[0], cvec.size() * sizeof(char));
    string s(charray);
}

练习9.42

int main(int argc, char* argv[])
{
    string s;
    s.reserve(100);
    char c;
    while (cin >> c) {
        s.push_back(c);
    }
}

练习9.43

void str_find_replace(string& s, string& oldVal, string& newVal) {
    auto it1 = s.begin(), it2 = newVal.begin(), it3 = newVal.end();
    for (; it1 != s.end() - oldVal.size(); it1++) {
        if (s.substr(it1 - s.begin(), oldVal.size()) == oldVal) {
            s.erase(it1 - s.begin(), oldVal.size());
            it1 = s.insert(it1, newVal.begin(), newVal.end());
            it1 += newVal.size();
        }
    }
}

练习9.44

void str_find_replace(string& s, string& oldVal, string& newVal) {
    auto it1 = s.begin(), it2 = newVal.begin(), it3 = newVal.end();
    for (; it1 != s.end() - oldVal.size(); it1++) {
        if (s.substr(it1 - s.begin(), oldVal.size()) == oldVal) {
            s.replace(it1, it1 + oldVal.size(), newVal);
            it1 += newVal.size();
        }
    }
}

练习9.45

string& last) {
    s.insert(0, prev);
    s.append(last);
}

练习9.46

string& last) {
    s.insert(0, prev);
    s.insert(s.size(), last);
}

练习9.47

只用find_first_of的

int main(int argc, char* argv[])
{
    string s = "ab2c3d7R4E6";
    string numbers("0123456789");
    auto pos = 0;
    while ((pos = s.find_first_of(numbers, pos)) != string::npos) {
        cout << s[pos++];
    }
    auto pos1 = 0, pos2 = 0;
    while ((pos2 = s.find_first_of(numbers, pos1)) != string::npos) {
        for (; pos1 != pos2; ++pos1)
            cout << s[pos1];
        ++pos1;
    }
    if (pos1 != s.find_last_not_of(numbers))cout << s[pos1];
    return 0;
}

只用find_first_not_of的

int main(int argc, char* argv[])
{
    string s = "ab2c3d7R4E6";
    string numbers("0123456789");
    auto pos1 = 0, pos2 = 0;
    while ((pos2 = s.find_first_not_of(numbers, pos1)) != string::npos) {
        for (; pos1 != pos2; ++pos1)
            cout << s[pos1];
        ++pos1;
    }
    if (pos1 != s.find_last_not_of(numbers))cout << s[pos1];
    auto pos = 0;
    while ((pos = s.find_first_not_of(numbers, pos)) != string::npos){
        cout << s[pos++];
    } 
    return 0;
}

练习9.48

string::npos

练习9.49

int main(int argc, char* argv[])
{
    string ascender("bdfhklt"); //上出头部分单词
    string descender("gjpqy");  //下出头部分单词
    std::ifstream ifs(argv[1]);
    string s,  maxs;
    auto max = 0;
    string::size_type pos;
    if (ifs)
    {
        while (!ifs.eof())
        {
            ifs >> s;
            if (s.find_first_of(ascender) == string::npos & s.find_first_of(descender) == string::npos&s.size()>max) {
                max = s.size();
                maxs = s;
            }
            s.clear();
        }
    }
    return 0;
}

练习9.50

计算整型值的string之和

int main(int argc, char* argv[])
{
    vector<string> strvec;
    long long ll = 0;
    for (const auto& it : strvec) {
        ll += stoll(it);
    }
    cout << ll << endl;
    return 0;
}

计算浮点值的string之和

int main(int argc, char* argv[])
{
    vector<string> strvec;
    long double ld = 0;
    for (const auto& it : strvec) {
        ld += stold(it);
    }
    cout << ld << endl;
    return 0;
}

练习9.51

#ifndef DATE_H_
#define DATE_H_
#include<string>
using std::string;
class Date
{
public:
    Date(string&);
    ~Date();

private:
    unsigned year;
    unsigned month;
    unsigned day;
    void str_to_month(string &str,string::size_type& pos);
};

Date::Date(string &s)
{
    string::size_type pos1, pos2;
    if (pos1 = s.find_first_of(",/") == string::npos) {
        pos1 = s.find_first_of(" ");
        pos2 = s.find_last_of(" ");
        str_to_month(s, pos1);
        day = stoul(s.substr(pos1 + 1, pos2));
        year = stoul(s.substr(pos2 + 1, s.size()));
    }
    else if (pos1 = s.find_first_of(",") == string::npos) {
        pos1 = s.find_first_of("/");
        pos2 = s.find_last_of("/");
        str_to_month(s, pos1);
        day = stoul(s.substr(pos1 + 1, pos2));
        year = stoul(s.substr(pos2 + 1, s.size()));
    }
    else if (pos1 = s.find_first_of("/") == string::npos) {
        pos1 = s.find_first_of(" ");
        pos2 = s.find_last_of(",");
        str_to_month(s, pos1);
        day = stoul(s.substr(pos1 + 1, pos2));
        year = stoul(s.substr(pos2 + 1, s.size()));
    }
}

Date::~Date()
{
}

inline void Date::str_to_month(string& s, string::size_type& pos1)
{
    if (s.substr(0, pos1) == "Jan" || s.substr(0, pos1) == "January") {
        month = 1;
    }
    else if (s.substr(0, pos1) == "Feb" || s.substr(0, pos1) == "February") {
        month = 2;
    }
    else if (s.substr(0, pos1) == "Mar" || s.substr(0, pos1) == "March") {
        month = 3;
    }
    else if (s.substr(0, pos1) == "Apr" || s.substr(0, pos1) == "April") {
        month = 4;
    }
    else if (s.substr(0, pos1) == "May" || s.substr(0, pos1) == "May") {
        month = 5;
    }
    else if (s.substr(0, pos1) == "Jun" || s.substr(0, pos1) == "June") {
        month = 6;
    }
    else if (s.substr(0, pos1) == "Jul" || s.substr(0, pos1) == "July") {
        month = 7;
    }
    else if (s.substr(0, pos1) == "Aug" || s.substr(0, pos1) == "August") {
        month = 8;
    }
    else if (s.substr(0, pos1) == "Sept" || s.substr(0, pos1) == "September") {
        month = 9;
    }
    else if (s.substr(0, pos1) == "Oct" || s.substr(0, pos1) == "October") {
        month = 10;
    }
    else if (s.substr(0, pos1) == "Nov" || s.substr(0, pos1) == "November") {
        month = 11;
    }
    else if (s.substr(0, pos1) == "Dec" || s.substr(0, pos1) == "December") {
        month = 12;
    }
    else {
        month = stoul(s.substr(0, pos1));
    }
}

练习9.52

unsigned get_operator_level(const char& c) {
    if (c == ')')return 4;
    else if (c == '*' || c == '/')return 3;
    else if (c == '+' || c == '-')return 2;
    else return 1;
}

int main(int argc, char* argv[])
{
    string s("(11+21)*13-(62+21)/53");
    string ns;
    stack<char> chars;
    stack<long> numbers;
    bool other = true;
    for (const auto&c:s) {
        if (isdigit(c)) {
            ns.insert(ns.end(), c);
        }
        else if(chars.empty()||c=='('){
            chars.push(c);
        }
        else if (c != ')') {
            while (!chars.empty() & get_operator_level(chars.top()) >= get_operator_level(c)) {
                ns.insert(ns.end(), chars.top());
                chars.pop();
            }
            chars.push(c);
            ns.insert(ns.end(), ' ');
        }
        else {
            while (chars.top() != '(') {
                ns.insert(ns.end(), chars.top());
                chars.pop();
            }
            chars.pop();
        }   
    }
    while (!chars.empty()) {
        ns.insert(ns.end(), chars.top());
        chars.pop();
    }
    for (const auto& c : ns) {
        if (isdigit(c) & other) {
            long num = 0;
            if (!numbers.empty()) {
                num = numbers.top();
                numbers.pop();
            }          
            num = num * 10 + c - '0';
            numbers.push(num);
        }
        else if (isdigit(c)) {
            numbers.push(c - '0');
            other = true;
        }
        else if (isspace(c)) {
            other = false;
        }
        else {
            long num1, num2;
            num2 = numbers.top();
            numbers.pop();
            num1 = numbers.top();
            numbers.pop();
            if (c == '+')numbers.push(num1 + num2);
            else if (c == '-')numbers.push(num1 - num2);
            else if (c == '*')numbers.push(num1 * num2);
            else if (c == '/')numbers.push(num1 / num2);
            other = false;
        }
    }
    return 0;
}

unsigned get_operator_level(const char& c) {
    if (c == ')')return 4;
    else if (c == '*' || c == '/')return 3;
    else if (c == '+' || c == '-')return 2;
    else return 1;
}

int main(int argc, char* argv[])
{
    string s("(11+21)*13-(62+21)/53");
    string ns;
    stack<char> chars;
    stack<long> numbers;
    bool other = true;
    for (const auto&c:s) {
        if (isdigit(c)) {
            ns.insert(ns.end(), c);
        }
        else if(chars.empty()||c=='('){
            chars.push(c);
        }
        else if (c != ')') {
            while (!chars.empty() & get_operator_level(chars.top()) >= get_operator_level(c)) {
                ns.insert(ns.end(), chars.top());
                chars.pop();
            }
            chars.push(c);
            ns.insert(ns.end(), ' ');
        }
        else {
            while (chars.top() != '(') {
                ns.insert(ns.end(), chars.top());
                chars.pop();
            }
            chars.pop();
        }   
    }
    while (!chars.empty()) {
        ns.insert(ns.end(), chars.top());
        chars.pop();
    }
    for (const auto& c : ns) {
        if (isdigit(c) & other) {
            long num = 0;
            if (!numbers.empty()) {
                num = numbers.top();
                numbers.pop();
            }          
            num = num * 10 + c - '0';
            numbers.push(num);
        }
        else if (isdigit(c)) {
            numbers.push(c - '0');
            other = true;
        }
        else if (isspace(c)) {
            other = false;
        }
        else {
            long num1, num2;
            num2 = numbers.top();
            numbers.pop();
            num1 = numbers.top();
            numbers.pop();
            if (c == '+')numbers.push(num1 + num2);
            else if (c == '-')numbers.push(num1 - num2);
            else if (c == '*')numbers.push(num1 * num2);
            else if (c == '/')numbers.push(num1 / num2);
            other = false;
        }
    }
    return 0;
}