Convert Sorted Array to Binary Search Tree
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
public TreeNode sortedArrayToBST(int[] num) { if (num.length == 0) { return null; } TreeNode head = helper(num, 0, num.length - 1); return head; } public TreeNode helper(int[] num, int low, int high) { if (low > high) { return null; } int mid = (low + high) / 2; TreeNode node = new TreeNode(num[mid]); node.left = helper(num, low, mid - 1); node.right = helper(num, mid + 1, high); return node; }
大道,在太极之上而不为高;在六极之下而不为深;先天地而不为久;长于上古而不为老