pat 1065 A+B and C (64bit)(20 分)(大数, Java)

1065 A+B and C (64bit)(20 分)

Given three integers A, B and C in [263​​,263​​], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false
 1 import java.math.BigDecimal;
 2 import java.math.BigInteger;
 3 import java.text.DecimalFormat;
 4 import java.util.Scanner;
 5 
 6 import javax.xml.namespace.QName;
 7 
 8 public class Main {
 9 
10     public static void main(String[] args) {
11         Scanner scan = new Scanner(System.in);
12         BigInteger a, b, c;
13         int t = scan.nextInt();
14         for (int i = 1; i <= t; ++i) {
15             a = scan.nextBigInteger();
16             b = scan.nextBigInteger();
17             c = scan.nextBigInteger();
18             String s = a.add(b).subtract(c).toString();
19             if (s.charAt(0) != '-' && s.charAt(0) != '0')
20                 System.out.println("Case #" + i + ": true");
21             else
22                 System.out.println("Case #" + i + ": false");
23         }
24     }
25 }

 

posted @ 2018-09-05 15:46  GetcharZp  阅读(146)  评论(0编辑  收藏  举报