全组合判断

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function isFullCombination(datas) {
  if (datas.length === 0) {
    return false;
  }
  const keys = Object.keys(datas[0]);
  const entries = keys.map((k) => [k, new Set()]);
  const fieldMap = new Map(entries);
  //Map(3) { '字段1' => Set(0) {}, '字段2' => Set(0) {}, '字段3' => Set(0) {} }
  const serializedSet = new Set();
  for (const data of datas) {
    const serialized = JSON.stringify(data)
    if(serializedSet.has(serialized)){
        return false
    }
    serializedSet.add(serialized)
    for (const key of keys) {
        const value = data[key]
        fieldMap.get(key).add(value);
    }
  }
//   console.log(fieldMap.values());
   
  const n1 = [...fieldMap.values()].reduce((a,b)=>a*b.size,1)
  const n2 = datas.length
  return  n2 === n1
}
const inputData = [
  { 字段1: "甲", 字段2: "a", 字段3: 1 },
  { 字段1: "甲", 字段2: "a", 字段3: 2 },
  { 字段1: "甲", 字段2: "a", 字段3: 3 },
  { 字段1: "甲", 字段2: "b", 字段3: 1 },
  { 字段1: "甲", 字段2: "b", 字段3: 2 },
  { 字段1: "甲", 字段2: "b", 字段3: 3 },
  { 字段1: "乙", 字段2: "a", 字段3: 1 },
  { 字段1: "乙", 字段2: "a", 字段3: 2 },
  { 字段1: "乙", 字段2: "a", 字段3: 3 },
  { 字段1: "乙", 字段2: "b", 字段3: 1 },
  { 字段1: "乙", 字段2: "b", 字段3: 2 },
  { 字段1: "乙", 字段2: "b", 字段3: 3 },
];
console.log(isFullCombination(inputData));

  

posted @   Gawaine  阅读(4)  评论(0编辑  收藏  举报
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