打印+动态规划

3302. 打印

ECNU-3302

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<string>
#include<cmath>
#include<map> 
#include<vector>
#include<unordered_map>
using namespace std;
typedef long long LL;
const int maxn=10000007;
LL dp[maxn];
int main(){
	int n;
	LL x,y;
	cin>>n>>x>>y;
	memset(dp,0,sizeof(dp));
	for(int i=1;i<=n;i++){
		if(i%2==0){//偶数 
			dp[i]=min(dp[i-1]+x,dp[i/2]+y);
		}else{//奇数 
			dp[i]=min(dp[i-1]+x,dp[(i+1)/2]+y+x);
		}
	}
	if(n==1)
		cout<<x<<endl;
	else{
		cout<<dp[n]<<endl;
	} 
	return 0;
}
posted @ 2020-10-04 19:44  Garrett_Wale  阅读(143)  评论(0编辑  收藏  举报