POJ Remmarguts' Date
题解:
次短路模板。
代码:
#include<cstdio> #include<iostream> using namespace std; #define inf 1e9 #define N 100005 #define S1 dis[x]+e[i].v #define S2 sdis[x]+e[i].v using namespace std; struct node { int to,next,v; } e[N<<1]; int head[N],cnt; void insert(int x, int y, int v) { e[++cnt].to=y; e[cnt].next=head[x]; e[cnt].v=v; head[x]=cnt; } int n,m,dis[N],sdis[N],q[N<<2]; bool inq[N]; void SPFA() { for(int i=1; i<=n; i++)dis[i]=sdis[i]=inf; dis[1]=0; q[0]=inq[1]=1; int l=0,r=1,t; while (l<r) { int x=q[l++]; for (int i=head[x]; i; i=e[i].next) { t=e[i].to; if (dis[t]>S1) { sdis[t]=dis[t]; dis[t]=S1; if (!inq[t])inq[t]=1,q[r++]=t; } if (dis[t]<S1&&sdis[t]>S1) { sdis[t]=S1; if (!inq[t])inq[t]=1,q[r++]=t; } if (sdis[t]>S2) { sdis[t]=S2; if (!inq[t])inq[t]=1,q[r++]=t; } } inq[x]=0; } } int main() { cin>>n>>m; for (int i=1,x,y,v; i<=m; i++) { cin>>x>>y>>v; insert(x,y,v); insert(y,x,v); } SPFA(); cout<<sdis[n]; return 0; }
#include <iostream> #include <queue> #include <cstdio> #include <cstring> #include <cstdlib> const int MAX = 999999; const int INF = 0x7fffffff; using namespace std; struct Edge { int num,len; bool operator <(const Edge &a)const { return a.len < len; } }temp; int u[MAX],v[MAX],w[MAX],dis[MAX],second[MAX],first[MAX / 4],next[MAX],n,r; void dijkstra() { priority_queue<Edge> que; dis[0] = 0; second[0] = INF; for(int i = 0; i < n; i++) dis[i] = second[i] = INF; temp.len = temp.num = 0; que.push(temp); while(!que.empty()) { Edge head = que.top(); que.pop(); if(head.len > second[head.num]) continue; int k = first[head.num]; while(k != -1) { int d = head.len + w[k]; if(dis[v[k]] > d) { swap(dis[v[k]], d); temp.len = dis[v[k]]; temp.num = v[k]; que.push(temp); } if(dis[v[k]] < d && second[v[k]] > d) { second[v[k]] = d; temp.len = second[v[k]]; temp.num = v[k]; que.push(temp); } k = next[k]; } } } int main() { scanf("%d%d",&n,&r); memset(first, -1, sizeof(first)); for(int i = 0; i < r; i++) { scanf("%d%d%d",&u[i],&v[i],&w[i]); u[i]--,v[i]--,next[i] = first[u[i]],first[u[i]] = i,u[i + r] = v[i]; v[i + r] = u[i],w[i + r] = w[i],next[i + r] = first[u[i + r]],first[u[i + r]] = i + r; } dijkstra(); printf("%d",second[n-1]); return 0; }
一世安宁