实现和线上汉诺塔移动问题
def hannuo(n,a,b,c):
if n == 1:
print(a,"->",c)
else:
hannuo(n-1,a,c,b)#将最后一个盘子移到c
print(a,"->",c)#将剩余的盘子移动c
hannuo(n-1,b,a,c)
n = int(input())
hannuo(n,"A","B","C")
汉诺塔问题可视化
#（参考修改于https://blog.csdn.net/weixin_44046046/article/details/88858031）
import turtle
turtle.setup(width=0.99, height=0.99)
class Stack:
def __init__(self):
self.items = []
def isEmpty(self):
return len(self.items) == 0
def push(self, item):
self.items.append(item)
def pop(self):
return self.items.pop()
def peek(self):
if not self.isEmpty():
return self.items[len(self.items) - 1]
def size(self):
return len(self.items)
turtle.done
def drawpole_3():
t = turtle.Turtle()
t.hideturtle()
def drawpole_1(k):
t.up()
t.pensize(10)
t.speed(100)
t.goto(400*(k-1), 300)
t.down()
t.goto(400*(k-1), -100)
t.goto(400*(k-1)-20, -100)
t.goto(400*(k-1)+20, -100)
drawpole_1(0)
drawpole_1(1)
drawpole_1(2)
def creat_plates(n):
plates=[turtle.Turtle() for i in range(n)]
for i in range(n):
plates[i].up()
plates[i].hideturtle()
plates[i].shape("square")
plates[i].shapesize(1,20-i)
plates[i].goto(-400,-90+20*i)
plates[i].showturtle()
return plates
def pole_stack():
poles=[Stack() for i in range(3)]
return poles
def moveDisk(plates,poles,fp,tp):
mov=poles[fp].peek()
plates[mov].goto((fp-1)*400,300)
plates[mov].goto((tp-1)*400,300)
l=poles[tp].size()
plates[mov].goto((tp-1)*400,-90+20*l)
def moveTower(plates,poles,height,fromPole, toPole, withPole):
if height >= 1:
moveTower(plates,poles,height-1,fromPole,withPole,toPole)
moveDisk(plates,poles,fromPole,toPole)
poles[toPole].push(poles[fromPole].pop())
moveTower(plates,poles,height-1,withPole,toPole,fromPole)
myscreen=turtle.Screen()
drawpole_3()
n=3
plates=creat_plates(n)
poles=pole_stack()
for i in range(n):
poles[0].push(i)
moveTower(plates,poles,n,0,2,1)
myscreen.exitonclick()
