Groovy In Action 笔记 (5) -- List 相关

list在Groovy中很重要，记录一下list的一些见操作:

def list = []
list << 2
// list >> 2 // invalid
assert list.size() == 1
assert list == [2]

//传统添加
list.add(3)
assert list.size() == 2 //groovy中统一的size 方法
assert list == [2,3]

list << "a"
assert list.size() == 3
assert list == [2,3,"a"] //groovy中不限制list中的数据类型，因为背后都是Object

def other_list = [3]
assert list - other_list == [2,"a"] // list可以直接相减

def other_list_a = [3,"b"]
assert list - other_list_a == [2,"a"] // list可以直接相减

assert list * 2 == [2,3,"a",2,3,"a"] // list可以乘以一个数，达到复制效果

assert list.intersect(other_list) == [3] // 取交集
assert list.reverse() == ["a",3,2]
assert !list.disjoint(other_list_a) // 判断有无交集

list.each {item -> println(item)}
assert list.collect({it*2}) == [4,6,"aa"] // map

def list_items = [1,2,3]
assert list_items.inject {x,y -> x * y} == 6 // reduce or fold
assert list_items.findAll {it % 2 == 0} == [2] //取值为偶数元素
assert list_items.join(",") == "1,2,3" // join　有时候很有用

def complex_list = [1,2,[3,4]]
assert complex_list.flatten() == [1,2,3,4]


//indexing
def long_list = [1,2,3,4,5,6,7,8]
assert long_list[1..3] == [2,3,4]
assert long_list[-1] == 8
assert long_list[-1..-3] == [8,7,6]
assert long_list[-1..0] == long_list.reverse() // 反转
assert long_list[-1..-8] == long_list.reverse() // 反转
assert long_list[1,2,4] == [2,3,5]
assert long_list[0..<2] == [1,2]

 

下面尝试一个简单的快排算法：

/**
 * @author ：ZackZhou
 * @date ：Created in 2020/9/1 5:42 PM
 * @description ：quick sort
 * @modified By：
 * @version:
 */


def quickSort(List input_list)
{
    if(input_list.size() < 2)
        return input_list

    int middle = input_list.size().intdiv(2)

    def middle_element = input_list.get(middle)

    def middle_list = input_list.findAll{item -> item == middle_element}
    def left_list = input_list.findAll{item -> item < middle_element}
    def right_list = input_list.findAll{item -> item > middle_element}

    return (quickSort(left_list) + middle_list + quickSort(right_list))
}

def raw_list = [3,24,5,6,6,7,82,6,7,2]

quickSort(raw_list).each {println(it)}