Android实现json的解析

新建一个Person类

/**
 * Created by Mr.Chan
 * Time 2022-11-15
 * Blog https://www.cnblogs.com/Frank-dev-blog/
 */
public class Person {
    private String id;
    private String name;
    private String age;

    public void setId(String id){
        this.id = id;
    }
    public String getId(){
        return this.id;
    }
    public void setName(String name){
        this.name = name;
    }
    public String getName(){
        return this.name;
    }
    public void setAge(String age){
        this.age = age;
    }
    public String getAge(){
        return this.age;
    }
    @Override
    public String toString() {
        return this.name + "age:" + this.age;
    }
}

  String json="[\n" +
            "    { \"id\":\"1\",\"name\":\"小明\",\"age\":\"16\" },\n" +
            "    { \"id\":\"2\",\"name\":\"小红\",\"age\":\"17\"  },\n" +
            "    { \"id\":\"3\",\"name\":\"小绿\",\"age\":\"18\" }\n" +
            "]";

这是json

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        for(Person person:parseEasyJson(json)){
            Log.e("--->",person.toString());
        }
    }
    String json="[\n" +
            "    { \"id\":\"1\",\"name\":\"小明\",\"age\":\"16\" },\n" +
            "    { \"id\":\"2\",\"name\":\"小红\",\"age\":\"17\"  },\n" +
            "    { \"id\":\"3\",\"name\":\"小绿\",\"age\":\"18\" }\n" +
            "]";

    private ArrayList<Person> parseEasyJson(String json){
        ArrayList<Person> persons = new ArrayList<Person>();
        try{
            JSONArray jsonArray = new JSONArray(json);
            for(int i = 0;i < jsonArray.length();i++){
                JSONObject jsonObject = (JSONObject) jsonArray.get(i);
                Person person = new Person();
                person.setId(i+"");
                person.setName(jsonObject.getString("name"));
                person.setAge(jsonObject.getString("age"));
                persons.add(person);
            }
        }catch (Exception e){e.printStackTrace();}
        return persons;
    }
}