实验6

TASK 1

  1 #include<stdio.h>
  2 #include<string.h>
  3 #define N 3
  4 
  5 typedef struct student
  6 {
  7     int id;
  8     char name[20];
  9     char subject[20];
 10     double perf;
 11     double mid;
 12     double final;
 13     double total;
 14     char level[10];
 15 }STU;
 16 
 17 void input(STU[],int);
 18 void output(STU[],int);
 19 void calc(STU[],int);
 20 int fail(STU[],STU[],int);
 21 void sort(STU[],int);
 22 
 23 int main()
 24 {
 25     STU st[N],fst[N];
 26     int k;
 27     
 28     printf("录入学生成绩信息：\n");
 29     input(st,N);
 30     
 31     printf("\n成绩处理...\n");
 32     calc(st,N);
 33     
 34     k = fail(st,fst,N);
 35     sort(st,N);
 36     printf("\n学生成绩排名情况：\n");
 37     output(st,N);
 38     
 39     printf("\n不及格学生信息:\n");
 40     output(fst,k);
 41     
 42     return 0;
 43 }
 44 
 45 void input(STU s[],int n)
 46 {
 47     int i;
 48     for(i=0;i<n;i++)
 49     {
 50         scanf("%d %s %s %lf %lf %lf",&s[i].id,&s[i].name,&s[i].subject,&s[i].perf,&s[i].mid,&s[i].final);
 51     }
 52 }
 53 
 54 void output(STU s[],int n)
 55 {
 56     int i;
 57     
 58     printf("-------------------\n");
 59     printf("学号   姓名   科目   平时   期中   期末   总评   等级\n");
 60         
 61     for(i=0;i<n;i++)
 62     {
 63         printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level);
 64     }
 65 }
 66 
 67 void calc(STU s[],int n)
 68 {
 69     int i;
 70     
 71     for(i=0;i<n;i++)
 72     {
 73         s[i].total=s[i].perf*0.2+s[i].mid*0.2+s[i].final*0.6;
 74         
 75     if(s[i].total>=90)
 76         strcpy(s[i].level,"优");
 77     else if(s[i].total>=80)
 78         strcpy(s[i].level,"良");
 79     else if(s[i].total>=70)
 80         strcpy(s[i].level,"中");
 81     else if(s[i].total>=60)
 82         strcpy(s[i].level,"及格");
 83     else
 84         strcpy(s[i].level,"不及格");    
 85     }
 86 }
 87 
 88 int fail(STU s[],STU t[],int n)
 89 {
 90     int i,cnt=0;
 91     
 92     for(i=0;i<n;i++)
 93     {
 94         if(s[i].total<60)
 95             t[cnt++]=s[i];
 96     }
 97     return cnt;
 98 }
 99 
100 void sort(STU s[],int n)
101 {
102     int i,j;
103     STU t;
104     
105     for(i=0;i<n;i++)
106     {
107         for(j=0;j<n;j++)
108         {
109             if(s[j].total<s[j+1].total)
110             {
111                 t=s[j];
112                 s[j]=s[j+1];
113                 s[j+1]=t;
114             }
115         }
116     }
117 }

TASK 2

 1 #include<stdio.h>
 2 #include<string.h>
 3 #define N 10
 4 #define M 80
 5 
 6 typedef struct
 7 {
 8     char name[M];
 9     char author[M];
10 }book;
11 
12 int main()
13 {
14     book x[N]={{"《一九八四》","乔治·奥威尔"},{"《美丽新世界》","赫胥黎"},{"《昨日的世界》","斯蒂芬·茨威格"},{"《万历十五年》","黄仁宇"},{"《一只特立独行的猪》","王小波"},{"《百年孤独》","马尔克斯"},{"《查令十字街84号》","海莲·汉芙"},{"《只是孩子》","帕蒂·史密斯"},{"《刀锋》","毛姆"},{"《沉默的大多数》","王小波"}};
15     book *ptr;
16     int i;
17     char author[M];
18     int found;
19     
20     printf("-------------------所有图书信息-------------------\n");
21     for(ptr=x;ptr<x+N;++ptr)
22         printf("%-30s%-30s\n",ptr->name,ptr->author);
23         
24         printf("\n-------------------按作者查询图书-------------------\n");
25         printf("输入作者名：");
26         gets(author);
27         found=0;
28         for(ptr=x;ptr<x+N;++ptr)
29             if(strcmp(ptr->author,author)==0)
30             {
31                 found=1;
32                 printf("%-30s%-30s\n", ptr->name, ptr->author);
33             }
34         if(!found)
35             printf("暂未收录该作者书籍!\n");
36         
37         return 0;
38 }

TASK 3

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #define N 80
 4 
 5 typedef struct filminfo
 6 {
 7     char name[N];
 8     char director[N];
 9     char region[N];
10     int year;
11     struct filminfo *next;
12 }film;
13 
14 void output(film *head);
15 film *insert(film *head,int n);
16 
17 int main()
18 {
19     int n;
20     film *head;
21     
22     head=NULL;
23     printf("输入影片数目：");
24     scanf("%d",&n);
25     
26     head=insert(head,n);
27     printf("\n所有影片信息如下：\n");
28     
29     output(head);
30     return 0;
31 }
32 
33 film *insert(film *head,int n)
34 {
35     int i;
36     film *p;
37     
38     for(i=1;i<=n;++i)
39     {
40         p=(film *)malloc(sizeof(film));
41         printf("请输入第%d部影片信息：",i);
42         scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
43         
44         p->next=head;
45         head=p;
46     }
47     return head;
48 }
49 
50 void output(film *head)
51 {
52     film *p;
53     p=head;
54     while(p!=NULL)
55     {
56         printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
57         p=p->next;
58     }
59 }

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #define N 80
 4 
 5 typedef struct filminfo
 6 {
 7     char name[N];
 8     char director[N];
 9     char region[N];
10     int year;
11     struct filminfo *next;
12 }film;
13 
14 void output(film *head);
15 film *insert(film *head,int n);
16 
17 int main()
18 {
19     int n;
20     film *head;
21     film *p;
22     
23     p=(film *)malloc(sizeof(film));
24     p->next=NULL;
25     head=p;
26 
27     printf("输入影片数目：");
28     scanf("%d",&n);
29     
30     head=insert(head,n);
31     printf("\n所有影片信息如下：\n");
32     
33     output(head);
34     return 0;
35 }
36 
37 film *insert(film *head,int n)
38 {
39     int i;
40     film *p;
41     
42     for(i=1;i<=n;++i)
43     {
44         p=(film *)malloc(sizeof(film));
45         printf("请输入第%d部影片信息：",i);
46         scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
47         
48         p->next=head;
49         head=p;
50     }
51     return head;
52 }
53 
54 void output(film *head)
55 {
56     film *p;
57     p=head;
58     while(p!=NULL)
59     {
60         printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
61         p=p->next;
62     }
63 }

修改后改变任意节点都不会影响头指针变量，不需要分类讨论改变节点的情况了

TASK 4

 

 1 #include<stdio.h>
 2 #define N 10
 3 
 4 typedef struct
 5 {
 6     char isbn[20];
 7     char name[80];
 8     char author[80];
 9     double sales_price;
10     int sales_count; 
11 }book;
12 
13 void output(book x[],int n);
14 void sort(book x[],int n);
15 double sales_amount(book x[],int n);
16 
17 int main()
18 {
19     book x[N]={{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
20                 {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 
21 , 30},
22                 {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
23                 {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
24                 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
25                 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
26                 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 
27 22.5, 44},
28                 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 
29 42},
30                 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
31                 {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}
32                 };
33 printf("图书销量排名（按销售册数）：\n");
34 sort(x,N);
35 output(x,N);
36 
37 printf("\n图书销售总额：%.2f\n",sales_amount(x,N));
38 
39 return 0; 
40 }
41 
42 void output(book x[],int n)
43 {
44     int i;
45     printf("   ISBN号   书名   作者   售价   销售册数  \n");
46     for (i = 0; i < n; i++) 
47     {
48         printf("  %s   %s   %s   %.2f   %d  \n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
49     }
50 }
51 
52 void sort(book x[],int n)
53 {
54     int i,j;
55     book t;
56     for(i=0;i<n-1;++i)
57     {
58         for(j=0;j<n-i-1;++j)
59         {
60             if(x[j].sales_count<x[j+1].sales_count)
61             {
62                 t=x[j];
63                 x[j]=x[j+1];
64                 x[j+1]=t;
65             }
66         }
67         
68     }
69 }
70 
71 double sales_amount(book x[],int n)
72 {
73     double totsals=0; 
74     int i;
75     for(i=0;i<n;i++)
76     {
77         totsals+=x[i].sales_price*x[i].sales_count;
78     }
79     return totsals;
80 }

 TASK 5

 1 #include<stdio.h>
 2 
 3 typedef struct
 4 {
 5     int year;
 6     int month;
 7     int day;
 8 }date;
 9 
10 void input(date *pd);
11 int day_of_year(date d);
12 int compare_dates(date d1,date d2);
13 
14 void test1()
15 {
16     date d;
17     int i;
18     
19     printf("输入日期：（以形如2024-12-16这样的形式输入）\n");
20     for(i=0;i<3;++i)
21     {
22         input(&d);
23         printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
24     }
25 }
26 
27 void test2()
28 {
29     date Alice_birth,Bob_birth;
30     int i;
31     int ans;
32     
33     printf("输入Alice和Bob出生日期：（以形如2024-12-16这样的形式输入）\n");
34     for(i=0;i<3;++i)
35     {
36         input(&Alice_birth);
37         input(&Bob_birth);
38         ans=compare_dates(Alice_birth,Bob_birth);
39         
40         if(ans==0)
41             printf("Alice和Bob一样大\n\n");
42         else if(ans==-1)
43             printf("Alice比Bob大\n\n");
44         else
45             printf("Alice比Bob小\n\n");
46     }
47 }
48 
49 int main()
50 {
51     printf("测试1：输入日期，打印输出这是一年中第多少天\n");
52     test1();
53     
54     printf("测试2：两个人年龄大小关系\n");
55     test2();
56 }
57 
58 void input(date *pd)
59 {
60     scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
61 }
62 
63 int day_of_year(date d)
64 {
65     int daynum[]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
66     int day_count=0;
67     int i;
68     
69     if(d.year%4==0&&d.year%100!=0||(d.year%400==0))
70     {
71         daynum[1]=29;
72     }
73     
74     for(i=0;i<d.month-1;++i)
75     {
76         day_count+=daynum[i];
77     }
78     day_count+=d.day;
79     return day_count;
80 }
81 
82 int compare_dates(date d1,date d2)
83 {
84     if(d1.year!=d2.year)
85         return d1.year-d2.year;
86     else if(d1.month!=d2.month)
87         return d1.month-d2.month;
88     else
89         return d1.day-d2.day;
90 }

 TASK 6

 1 #include<stdio.h>
 2 #include<string.h>
 3 
 4 enum role{admin,student,teacher};
 5 
 6 typedef struct
 7 {
 8     char username[20];
 9     char password[20];
10     enum role type;
11 }account;
12 
13 void output(account x[],int n);
14 
15 int main()
16 {
17     account x[] = { {"A1001", "123456", student},
18                      {"A1002", "123abcdef", student},
19                      {"A1009", "xyz12121", student}, 
20                     {"X1009", "9213071x", admin},
21                      {"C11553", "129dfg32k", teacher},
22                      {"X3005", "921kfmg917", student}
23                  };
24      int n;
25      n=sizeof(x)/sizeof(account);
26      output(x,n);
27      
28      return 0;
29 }
30 
31 void output(account x[], int n) 
32 {
33     int i,j;
34     for (i = 0; i < n; i++) {
35         printf("%s\t\t", x[i].username);
36         for (j = 1; j < strlen(x[i].password); j++) 
37         {
38             printf("*");
39         }
40         printf("\t\t");
41         switch (x[i].type) 
42         {
43             case admin:
44                 printf("admin\n");
45                 break;
46             case student:
47                 printf("student\n");
48                 break;
49             case teacher:
50                 printf("teacher\n");
51                 break;
52         }
53     }
54 }

 TASK 7

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 typedef struct
 5 {
 6     char name[20];
 7     char phone[12];
 8     int vip;
 9 } contact;
10 
11 void set_vip_contact(contact x[], int n, char name[])
12 {
13     int i;
14     for (i = 0; i < n; i++)
15     {
16         if (strcmp(x[i].name, name) == 0)
17         {
18             x[i].vip = 1;
19             break;
20         }
21     }
22 }
23 
24 void output(contact x[], int n)
25 {
26     int i;
27     for (i = 0; i < n; i++)
28     {
29         printf("%-19s%-15s", x[i].name, x[i].phone);
30         if (x[i].vip)
31             printf("%5s", "*");
32         printf("\n");
33     }
34 }
35 
36 void display(contact x[], int n)
37 {
38     int i, j;
39     contact temp;
40     for (i = 0; i < n - 1; i++)
41     {
42         for (j = 0; j < n - 1 - i; j++)
43         {
44             if (x[j + 1].vip && !x[j].vip) 
45             {
46                 temp = x[j];
47                 x[j] = x[j + 1];
48                 x[j + 1] = temp;
49             } 
50             else if (x[j].vip == x[j + 1].vip && strcmp(x[j].name, x[j + 1].name) > 0)
51             {
52                 temp = x[j];
53                 x[j] = x[j + 1];
54                 x[j + 1] = temp;
55             }
56         }
57     }
58     output(x, n);
59 }
60 
61 #define N 10
62 int main()
63 {
64     contact list[N] = 
65     {
66         {"刘一", "15510846604", 0},
67         {"陈二", "18038747351", 0},
68         {"张三", "18853253914", 0},
69         {"李四", "13230584477", 0},
70         {"王五", "15547571923", 0},
71         {"赵六", "18856659351", 0},
72         {"周七", "17705843215", 0},
73         {"孙八", "15552933732", 0},
74         {"吴九", "18077702405", 0},
75         {"郑十", "18820725036", 0}
76     };
77     int vip_cnt, i;
78     char name[20];
79 
80     printf("显示原始通讯录信息\n");
81     output(list, N);
82 
83     printf("\n输入要设置的紧急联系人个数：");
84     scanf("%d", &vip_cnt);
85     printf("输入%d个紧急联系人姓名：\n", vip_cnt);
86     for (i = 0; i < vip_cnt; ++i)
87     {
88         scanf("%s", name);
89         set_vip_contact(list, N, name);
90     }
91 
92     printf("\n显示通讯录列表：（按姓名字典序升序排列，紧急联系人最先显示）\n");
93     display(list, N);
94 
95     return 0;
96 }

 

posted @ 2024-12-19 16:57  Florence11  阅读(4)  评论(0)  编辑  收藏  举报