LeetCode 103. 二叉树的锯齿形层序遍历

思路#

方法：层序遍历#

class Solution {
public:
    vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
        vector<vector<int>> ans;
        if (!root) {
            return ans;
        }

        queue<TreeNode*> nodeQueue;
        nodeQueue.push(root);
        bool isOrderLeft = true;

        while (!nodeQueue.empty()) {
            deque<int> levelList;
            int size = nodeQueue.size();
            for (int i = 0; i < size; ++i) {
                auto node = nodeQueue.front();
                nodeQueue.pop();
                if (isOrderLeft) {
                    levelList.push_back(node->val);
                } else {
                    levelList.push_front(node->val);
                }
                if (node->left) {
                    nodeQueue.push(node->left);
                }
                if (node->right) {
                    nodeQueue.push(node->right);
                }
            }
            ans.emplace_back(vector<int>{levelList.begin(), levelList.end()});
            isOrderLeft = !isOrderLeft;
        }

        return ans;
    }
};

 

原文：LeetCode官方题解 - 二叉树的锯齿形层序遍历