5

1

源代码

#include<stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
void find_min_max(int x[], int n, int *pmin, int *pmax);

int main() {
    int a[N];
    int min, max;

    printf("录入%d个数据:\n", N);
    input(a, N);

    printf("数据是: \n");
    output(a, N);

    printf("数据处理...\n");
    find_min_max(a, N, &min, &max);

    printf("输出结果:\n");
    printf("min = %d, max = %d\n", min, max);
    getchar();
    getchar();
    return 0;
}

void input(int x[], int n) {
    int i;

    for(i = 0; i < n; ++i)
        scanf("%d", &x[i]);
}

void output(int x[], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

void find_min_max(int x[], int n, int *pmin, int *pmax) {
    int i;
    
    *pmin = *pmax = x[0];

    for(i = 0; i < n; ++i)
        if(x[i] < *pmin)
            *pmin = x[i];
        else if(x[i] > *pmax)
            *pmax = x[i];
}

找到最大元素,最小元素

输入第一个数据

结果

#include <stdio.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
int *find_max(int x[], int n);

int main() {
    int a[N];
    int *pmax;

    printf("录入%d个数据:\n", N);
    input(a, N);

    printf("数据是: \n");
    output(a, N);

    printf("数据处理...\n");
    pmax = find_max(a, N);

    printf("输出结果:\n");
    printf("max = %d\n", *pmax);

    return 0;
}

void input(int x[], int n) {
    int i;

    for(i = 0; i < n; ++i)
        scanf("%d", &x[i]);
}

void output(int x[], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

int *find_max(int x[], int n) {
    int max_index = 0;
    int i;

    for(i = 0; i < n; ++i)
        if(x[i] > x[max_index])
            max_index = i;
    
    return &x[max_index];
}

结果

返回最大元素的地址

2

源代码

#include <stdio.h>
#include <string.h>
#define N 80

int main() {
    char s1[N] = "Learning makes me happy";
    char s2[N] = "Learning makes me sleepy";
    char tmp[N];

    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));

    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    printf("\nswapping...\n");
    strcpy(tmp, s1);
    strcpy(s1, s2);
    strcpy(s2, tmp);

    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
    getchar();
    getchar();
    return 0;
}

结果

80 数组大小 数组长度

 

交换

#include <stdio.h>
#include <string.h>
#define N 80

int main() {
    char *s1 = "Learning makes me happy";
    char *s2 = "Learning makes me sleepy";
    char *tmp;

    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));

    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    printf("\nswapping...\n");
    tmp = s1;
    s1 = s2;
    s2 = tmp;

    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
    getchar();
    getchar();
    return 0;
}

 

结果

s1地址的大小

s1字符串的长度

源代码直接定义一个指向字符串的指针

换的代码先定义一个指针,再指向字符串

地址

没有

3

源代码

#include <stdio.h>

int main() {
    int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
    int i, j;
    int *ptr1;     // 指针变量,存放int类型数据的地址
    int(*ptr2)[4]; // 指针变量,指向包含4个int元素的一维数组

    printf("输出1: 使用数组名、下标直接访问二维数组元素\n");
    for (i = 0; i < 2; ++i) {
        for (j = 0; j < 4; ++j)
            printf("%d ", x[i][j]);
        printf("\n");
    }

    printf("\n输出2: 使用指针变量ptr1(指向元素)间接访问\n");
    for (ptr1 = &x[0][0], i = 0; ptr1 < &x[0][0] + 8; ++ptr1, ++i) {
        printf("%d ", *ptr1);

        if ((i + 1) % 4 == 0)
            printf("\n");
    }
                         
    printf("\n输出3: 使用指针变量ptr2(指向一维数组)间接访问\n");
    for (ptr2 = x; ptr2 < x + 2; ++ptr2) {
        for (j = 0; j < 4; ++j)
            printf("%d ", *(*ptr2 + j));
        printf("\n");
    }
    getchar();
    getchar();
    return 0;
}

结果

ptr为指向含4个元素的一维整形数组的指针变量

ptr 为由4个指向整形的指针变量组成的指针数组

4

源代码

#include <stdio.h>
#define N 80

void replace(char *str, char old_char, char new_char); // 函数声明

int main() {
    char text[N] = "Programming is difficult or not, it is a question.";

    printf("原始文本: \n");
    printf("%s\n", text);

    replace(text, 'i', '*'); // 函数调用 注意字符形参写法,单引号不能少

    printf("处理后文本: \n");
    printf("%s\n", text);

    return 0;
}

// 函数定义
void replace(char *str, char old_char, char new_char) {
    int i;

    while(*str) {
        if(*str == old_char)
            *str = new_char;
        str++;
    }
}

结果

将i替换为#include <stdio.h>

#define N 80

char *str_trunc(char *str, char x);

int main() {
    char str[N];
    char ch;

    while(printf("输入字符串: "), gets(str) != NULL) {
        printf("输入一个字符: ");
        ch = getchar();

        printf("截断处理...\n");
        str_trunc(str, ch);         // 函数调用

        printf("截断处理后的字符串: %s\n\n", str);
        getchar();
    }

    return 0;
}
char *str_trunc(char *str,char x){
    char *p = str;
    while (*p!= '\0') {
        if (*p == x) {
            *p = '\0';           
        }
        p++;
    }
    return str;
}

  

结果

抵消回车键带来的影响

6

源代码

int check_id(char *str) {
    int len = strlen(str);
    if (len!= 18) return 0;

    int sum = 0;
    int weight[] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
    char checksum[] = {'1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};

    for (int i = 0; i < 17; ++i) {
        if (str[i] < '0' || str[i] > '9') return 0;
        sum += (str[i] - '0') * weight[i];
    }

    int index = sum % 11;
    if (str[17] == checksum[index]) return 1;
getchar();
getchar();
return 0; }

结果

实验7

源代码

#include <stdio.h>
#define N 80
void encoder(char *str, int n); // 函数声明
void decoder(char *str, int n); // 函数声明

int main() {
    char words[N];
    int n;

    printf("输入英文文本: ");
    gets(words);

    printf("输入n: ");
    scanf("%d", &n);

    printf("编码后的英文文本: ");
    encoder(words, n);      // 函数调用
    printf("%s\n", words);

    printf("对编码后的英文文本解码: ");
    decoder(words, n); // 函数调用
    printf("%s\n", words);
    getchar();
    getchar();
    return 0;
}
void encoder(char *str, int n) {
    int i;
    for(i=0;str[i]!='\0';i++){
        if(str[i]>='a'&&str[i]<='z'){
            str[i]=(str[i]-'a'+n)%26+'a';
        }
        else if(str[i]>='A'&&str[i]<='Z'){
            str[i]=(str[i]-'A'+n)%26+'A';
        }
    }
    
}
void decoder(char *str, int n) {
    int i;
    for(i=0;str[i]!='\0';i++){
        if(str[i]>='a'&&str[i]<='z'){
            str[i]=(str[i]-'a'-n+26)%26+'a';
        }
        else if(str[i]>='A'&&str[i]<='Z'){
            str[i]=(str[i]-'A'-n+26)%26+'A';
        }
    }
}

 

结果

实验八

源代码

#include <stdio.h>
#include<string.h>
int main(int argc, char *argv[]) {
    int i;
    int j;
    char* temp;
    for(i = 1; i < argc; i++){
        for(j=1;j<argc-i;j++){
            if(strcmp(argv[j],argv[j+1])>0){
                temp = argv[j];
                argv[j] = argv[j+1];
                argv[j+1] = temp;
            }

        }
    }
    for(i = 1; i < argc; ++i)
        printf("hello, %s\n", argv[i]);
    getchar();
    return 0;
}

结果

 

posted @ 2024-12-08 13:37  毛天佑202483290413  阅读(6)  评论(0编辑  收藏  举报