misaka oj 1012 最大公因数和最小公倍数
先是用逐差法求最大公因数:
先求两整数a,b的差,以差代替较大的数,如此循环,直到两个数相等为止,则这个数既是a,b的最大公因数;
a,b的最小公倍数=a*b/最大公因数;
题目地址:http://oj.misakamm.com/JudgeOnline/problem.php?id=1012
#include <fstream>
int main()
{
int a , b , gcda , gcdb , lcm ;
scanf( "%d%d" , &a , &b ) ;
gcda = a ;
gcdb = b ;
while ( gcda != gcdb )
{
if ( gcda == 1 || gcdb == 1 )
{
gcda = gcdb = 1 ;
break ;
}
if ( gcda > gcdb )
{
gcda -= gcdb ;
}
else
{
gcdb -= gcda ;
}
}
lcm = a * b / gcda ;
printf( "%d\n%d" , gcda , lcm ) ;
}