markdown

hello

\((a+b)^2 = a^2 + 2ab + b^2\)

\(f_{i,j}=max\texttt{\{} f_{i-1,j}+a_i,f_{i-1,0} \texttt{\}}\)

\(f_{i} = min\texttt{\{} f_j + S_i - S_j \texttt{\}}\)

\(\texttt{%}\)

\(\texttt{\}}\)
\(O(n)\)

\(ax^2+bx+c=0\)
$ x = {-b \pm \sqrt{b^2-4ac} \over 2a}. \( \) x = {-b +\sqrt{b^2-4ac} \over 2a}. \( \) \sqrt{a}\ \( \) \pm \( \) {x^2 \over a^2} + {y^2 \over b^2} =1 \( \) _sum $

#include<iostream>
#include<cmath>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<queue>
using namespace std;
typedef long long LL;
#define mem(a,b) memset(a,b,sizeof(a))
typedef pair<int,int> PII;
inline int read()
{
	int x=0,f=1;char c=getchar();
	while(!isdigit(c)){if(c=='-')f=-1;c=getchar();}
	while(isdigit(c)){x=x*10+c-'0';c=getchar();}
	return x*f;
}

int main()
{

	return 0;
}

Dijkstra
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Rolling Sky

题解#

测试数据##

总结###

酯化反应
脱水缩合
静电感应

双曲线###

http://www.cnblogs.com/FYH-SSGSS/p/7348163.html
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