PAT乙级1004 成绩排名

我的解法（提示格式错误）

#include <stdio.h>

int main()
{
    int n, i,min,max,min_index,max_index;
    scanf("%d",&n);
    char c = getchar();
    //char* a[1000];
    char a[1000][30];
    int b[1000];
    for(i=0;i<n;i++)
    {
        int space = 0,j=0;
        char ch;
        while(space<=1)
        {
            ch = getchar();
            if(ch == ' ') space++;
            a[i][j++] = ch;
        }
        scanf("%d",&b[i]);
        char ll = getchar();
        if(i==0)
        {
            min = b[i];
            min_index =i;
            max = b[i];
            max_index =i;
        }
        if (b[i]>max) 
        {
            max = b[i];
            max_index =i;
        }
        if (b[i]<min)
        {
            min = b[i];
            min_index =i;
        }
    }
    printf("%s\n",a[max_index]);
    printf("%s\n",a[min_index]);
}

博客解法：

#include <stdio.h>
#include <string.h>

int main()
{
    int N;
    scanf("%d", &N);

    char maxname[11], minname[11], curname[11],
        maxid[11], minid[11], curid[11];
    int maxgrade = -1, mingrade = 101, curgrade;

    for(int i = 0; i < N; i++)
    {
        scanf("%s %s %d", curname, curid, &curgrade);

        if(curgrade > maxgrade)
        {
            strcpy(maxname, curname);
            strcpy(maxid, curid);
            maxgrade = curgrade;
        }
        if(curgrade < mingrade)
        {
            strcpy(minname, curname);
            strcpy(minid, curid);
            mingrade = curgrade;
        }
    }

    printf("%s %s\n%s %s", maxname, maxid, minname, minid);

    return 0;
}