摘要: A int T, n, a[105], dp[105][2]; signed main(void) { for (read(T); T; T--) { read(n); int mx = 0, id = 0; for (int i = 1; i <= n; i++) { read(a[i]); if 阅读全文
posted @ 2024-09-28 00:31 EternalEpic 阅读(468) 评论(3) 推荐(1) 编辑
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