Python 双向链表
操作
- is_empty() 链表是否为空
- length() 链表长度
- travel() 遍历链表
- add(item) 链表头部添加
- append(item) 链表尾部添加
- insert(pos, item) 指定位置添加
- remove(item) 删除节点
- search(item) 查找节点是否存在
class Node(object): """双向链表节点""" def __init__(self, item): self.item = item self.next = None self.prev = None class DLinkList(object): """双向链表""" def __init__(self): self._head = None def is_empty(self): """判断链表是否为空""" return self._head == None def length(self): """返回链表的长度""" cur = self._head count = 0 while cur != None: count += 1 cur = cur.next return count def travel(self): """遍历链表""" cur = self._head while cur != None: print cur.item, cur = cur.next print "" def add(self, item): """头部插入元素""" node = Node(item) if self.is_empty(): # 如果是空链表,将_head指向node self._head = node else: # 将node的next指向_head的头节点 node.next = self._head # 将_head的头节点的prev指向node self._head.prev = node # 将_head 指向node self._head = node def append(self, item): """尾部插入元素""" node = Node(item) if self.is_empty(): # 如果是空链表,将_head指向node self._head = node else: # 移动到链表尾部 cur = self._head while cur.next != None: cur = cur.next # 将尾节点cur的next指向node cur.next = node # 将node的prev指向cur node.prev = cur def search(self, item): """查找元素是否存在""" cur = self._head while cur != None: if cur.item == item: return True cur = cur.next return False
def insert(self, pos, item): """在指定位置添加节点""" if pos <= 0: self.add(item) elif pos > (self.length()-1): self.append(item) else: node = Node(item) cur = self._head count = 0 # 移动到指定位置的前一个位置 while count < (pos-1): count += 1 cur = cur.next # 将node的prev指向cur node.prev = cur # 将node的next指向cur的下一个节点 node.next = cur.next # 将cur的下一个节点的prev指向node cur.next.prev = node # 将cur的next指向node cur.next = node
def remove(self, item): """删除元素""" if self.is_empty(): return else: cur = self._head if cur.item == item: # 如果首节点的元素即是要删除的元素 if cur.next == None: # 如果链表只有这一个节点 self._head = None else: # 将第二个节点的prev设置为None cur.next.prev = None # 将_head指向第二个节点 self._head = cur.next return while cur != None: if cur.item == item: # 将cur的前一个节点的next指向cur的后一个节点 cur.prev.next = cur.next # 将cur的后一个节点的prev指向cur的前一个节点 cur.next.prev = cur.prev break cur = cur.next
if __name__ == "__main__": ll = DLinkList() ll.add(1) ll.add(2) ll.append(3) ll.insert(2, 4) ll.insert(4, 5) ll.insert(0, 6) print "length:",ll.length() ll.travel() print ll.search(3) print ll.search(4) ll.remove(1) print "length:",ll.length() ll.travel()